We have 4 deliveries ( 12 1/3 , 8 3/4, 17 2/8 and 23 2/3 miles ) and also the final delivery : 10 5/10 miles = 10 1/2 miles.
We have to add up all the deliveries and to divide the result by 5:
( 12 1/3 + 8 3/4 + 17 1/4 + 23 2/3 + 10 1/2 ) : 5 =
= 72 1/2 : 5 = 72.5 : 5 = 14.5 = 14 1/2
Answer: The average distance for all segments of this trip is 14 1/2 miles.
Answer:
4
Step-by-step explanation:
There are 5 points. So there are 4 segments. The segments are the line between two points.
Answer:
Sample size n = 1382
so correct option is D) 1382
Step-by-step explanation:
given data
confidence level = 99 %
margin of error = 3%
probability = 25 %
to find out
How large a sample size needed
solution
we know here P = 25 %
so 1 - P = 1 - 0.25
1 - P = 0.75
and we know E margin of error is 0.03 so value of Z for 99%
α = 1 - 99% = 1 - 0.99
α = 0.01
and 
= 
= 0.005
so Z is here
= 2.576
so
sample size will be
Sample size n = 
put here value
Sample size n = (\frac{2.576}{0.03})^2 * 0.25 * 0.75
Sample size n = 1382
so correct option is D) 1382
Me just so I can ask a question
Answer: See below
Step-by-step explanation:
27. -(a-3)
28. (b-1)(b+3)
29. (c+4)(c+5)
30. d(d+5)
31. -(3/4)(2e-5)
Sorry - I don't have time to enter the details. Look for areas where the expressions can be factored in a manner that forms as many equivalent expressions in both the numerator and denominator.
For example: In problem 30:
(5d-20)/(d^2+d-20) * [??]/20d = 1/4
Factor:
<u>(5(d-4))</u> <u>d(d+5)</u> = 1/4
(d-4)(d+5<u>)</u> 20d
The (d-4), d+5, and d terms cancel, leaving
5/20 = 1/4
