The answer is 65, hope this helps
The absolute value of I9I is 9 and -9 but I would put 9 first if you can only pick one
Answer:
x = 1 - 5t
y = t
z = 1 - 5t
Step-by-step explanation:
For the equation of a line, we need a point and a direction vector. We are given a point (1, 0, 1).
Since the line is suppose to be a tangent to the given curve at the point (1, 0, 1), we need to find a tangent vector for which the curve passes through that point.
We have x = e^(-5t)cos5t
at t = 1, x = e^(-5)cos5
at t = 0, x = 1
y = e^(-5t)sin5t
at t = 1, y = e^(-5)sin5
at t = 0, y = 0
z = e^(-5t)
at t = 1, z = e^(-5)
at t = 0, z = 1
Clearly, the only parameter value for which the curve passes through the point (1, 0, 1) is t = 0.
In vector notation, the curve
r(t) = xi + yj + zk
= e^(-5t)cos5t i + e^(-5t)sin5t j + e^(-5t) k
r'(t) = [-5e^(-5t)cos5t - e^(-5t)sin5t] i +[e^(-5t)cos5t - 5e^(-5t)sin5t] j - 5e^(-5t) k
r'(0) = -5i + j - 5k
is a vector tangent at the point.
We get the parametric equation from this.
x = x(0) + tx'(0)
= 1 - 5t
y = y(0) + ty'(0)
= t
z = z(0) + tz'(0)
= 1 - 5t
C is correct. So it’s asking given any whole number Squared you will get another whole number squared but in reality there are only a few numbers like that and they are called perfect squares(4 16 36 81 121)
Answer:
y=-1/2x+3/2
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(-1-1)/(5-1)
m=-2/4
m=-1/2
y-y1=m(x-x1)
y-1=-1/2(x-1)
y=-1/2x+1/2+1
y=-1/2x+1/2+2/2
y=-1/2x+3/2
