Answer:
Let's choose the three odd consecutive numbers 1, 3, and 5.
3^2=9
1•5=5
9-5=4
Let's try the same thing, but with the numbers 101, 103, and 105.
103^2=10609
101•105=10605
10609-10605=4
So, yes, the square of the second number out of three consecutive odd numbers is four greater than the product of the first and the third numbers.
The mistake is in Step 1. The solver should have also squared 
when squaring the other side of the equation.
<h3>Correctly solving</h3>
A it’s a I think ok because I’m new
Answer:
False
Step-by-step explanation:
Pos and negs cannot be perfect square trinomials
