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3 years ago

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Which is the correct interpretation of the x-intercepts of the function? Their difference is the number of the most promo codes

in a single day. Their sum is the total number of days the number of codes increased. Their sum is the total number of promo codes the publicist is releasing before the new record. Their difference is the number of days the first promo codes were released before the new record.

1 answer:

GrogVix [38]3 years ago

4 0

Answer:

d

Step-by-step explanation:

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This data set represents the number of cups of coffee sold in a café between 8 a.m. and 10 a.m. every day for 14 days.

san4es73 [151]

Put the numbers in order...
4,5,6,6,7,8,9,9,10,10,12,12,14,15

Q1 = (6 + 6) / 2 = 12/2 = 6
Q2 (median) = (9 + 9)/2 = 18/2 = 9
Q3 = (12 + 12) / 2 = 24/2 = 12

Q3 - Q1 = 12 - 6 = 6 (this is actually the interquartile range (IQR)

8 0

3 years ago

Read 2 more answers

Which represents the inverse of the function f(x) = 4x?

Cloud [144]

To find the inverse function simply replace "x" by "y", replace "y" by "x", and solve for y
f(x)=4x
y=4x
x=4y
y=x/4 or h(x)=(1/4)x

8 0

2 years ago

Helpppppppppppppppppp

irina [24]

Option D:

$\left(y^{2}+3 y+7\right)\left(8 y^{2}+y+1\right)=8 y^{4}+25 y^{3}+60 y^{2}+10y+7$

Solution:

Given expression is $\left(y^{2}+3 y+7\right)\left(8 y^{2}+y+1\right)$ .

<u>To find the product of the expression:</u>

$\left(y^{2}+3 y+7\right)\left(8 y^{2}+y+1\right)$

Multiply each term of the first term with each term of the 2nd term.

$=y^{2}\left(8 y^{2}+y+1\right) +3 y\left(8 y^{2}+y+1\right) +7\left(8 y^{2}+y+1\right)$

Using the exponent rule: $a^m \cdot a^n = a^{m+n}$

$=\left(8 y^{4}+y^3+y^2\right) +\left(24 y^{3}+3y^2+3y\right) +\left(56 y^{2}+7y+7\right)$

$=8 y^{4}+y^3+y^2+24 y^{3}+3y^2+3y+56 y^{2}+7y+7$

Arrange the terms with same power.

$=8 y^{4}+y^3+24 y^{3}+y^2+3y^2+56 y^{2}+7y+3y+7$

$=8 y^{4}+25 y^{3}+60 y^{2}+10y+7$

Hence option D is the correct answer.

$\left(y^{2}+3 y+7\right)\left(8 y^{2}+y+1\right)=8 y^{4}+25 y^{3}+60 y^{2}+10y+7$

6 0

3 years ago

The ages of trees in a forest are normally distributed with a mean of 25 years and a standard deviation of 4. Approximately what

harkovskaia [24]

Answer:

78.88%

Step-by-step explanation:

We have been given that

$\mu=25,\sigma=4,x_1=20,x_2=30$

The z-score formula is given by

$z-\text{score}=\frac{x-\mu}{\sigma}$

For $x_1=20$

$z_1=\frac{20-25}{4}\\\\z_1=-1.25$

For $x_2=30$

$z_2=\frac{30-25}{4}\\\\z_2=1.25$

Now, we find the corresponding probability from the standard z score table.

For the z score -1.25, we have the probability 0.1056

For the z score 1.25, we have the probability 0.8944

Therefore, the percent of the trees that are between 20 and 30 years old is given by

0.8944 - 0.1056

= 0.7888

=78.88%

6 0

4 years ago

Read 2 more answers

5(x+3)-7(6-3)+29=50-3(8-x)

Sveta_85 [38]

Answer:

$\quad x=\frac{3}{2}$

Step-by-step explanation:

$7\left(6-3\right)=21$ , $\mathrm{Expand\:}5\left(x+3\right)-21+29:\quad5x+23$ , $\mathrm{Expand\:}50-3\left(8-x\right):\quad 3x+26$ , Subtract 23 and 3x from both sides and simplify: $2x=3$ , Divide both sides by 2 and simplify: $x=\frac{3}{2}$

<em>Hope this helps!!!</em>

6 0

3 years ago