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3 years ago

After a cab ride, Jacob’s total fare was $35. He paid the cab driver a 15% tip. How much was the tip?

Mathematics

2 answers:

Cerrena [4.2K]3 years ago

8 0

It’s 5.25 your welcome

lord [1]3 years ago

3 0

The answer is 7.50 your welcome

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Kenji is saving money to buy a new bicycle that costs $125. So far he has saved his weekly allowance of $5 for the past 8 weeks.

Alla [95]

Answer:

$85

Step-by-step explanation:

$125 - $5 - $35 = $85

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3 years ago

Please helpp (exponents)

pshichka [43]

Answer:

the answer is 27

Step-by-step explanation:

for the show your work all you have to do is write 3x3x3=27

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3 years ago

What is (27/8)^-2/3 ?

Paraphin [41]

Answer:

Step-by-step explanation:

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3 years ago

Professor Turner wrote the expression below on the chalkboard for his team at the Research Center. He asked the scientists there

Lynna [10]

Answer:

12x + 18y + 6z + 4x - 4z

Step-by-step explanation:

Given the expression : 3(4x + 6y + 2z) + 4(x – z)

To eliminate the parenthesis ; we use the distributive property :

3(4x + 6y + 2z) + 4(x – z) becomes ;

3*4x + 3*6y + 3*2z + 4*x + 4*-z

12x + 18y + 6z + 4x - 4z

Hence,

12x + 4x + 18y + 6z - 4z

16x + 18y + 2z

6 0

3 years ago

Find the six trigonometric function values for angle ∅ where its adjacent side is -9 and its hypotenuse is 41. (Theta is located

arsen [322]

Check the picture below.

$\bf \textit{using the pythagorean theorem}
\\\\
c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\sqrt{41^2-(-9)^2}=b\implies \sqrt{1681-81}=b\\\\\\ \sqrt{1600}=b\implies 40=b\\\\
-------------------------------$

$\bf sin(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{hypotenuse}{41}}\qquad~~ cos(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{hypotenuse}{41}}\qquad~~ tan(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{adjacent}{-9}}
\\\\\\
csc(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{opposite}{40}}\qquad ~~sec(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{adjacent}{-9}}\qquad ~~cot(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{opposite}{40}}$

3 0

3 years ago