For problems 6-9, using the formula net Force = 6) a=2 m/s2 8 kg F = m•a =
2 answers:
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Answer:
m∠CAB = 66°
m∠CAD = 24°
Step-by-step explanation:
<em>m∠CAB</em>
The given parameters are;
The measure of arc m = 228°
The diameter of the given circle =
The tangent to the circle =
The measure of m∠CAB and m∠CAD = Required
By the tangent and chord circle theorem, we have;
m∠CAB = (1/2) × m
However, we have;
m + m
= 360° the sum of angles at the center of a circle is 360°
∴ m = 360° - m
Which gives;
m = 360° - 228° = 132°
m = 132°
Therefore;
m∠CAB = (1/2) × 132° = 66°
m∠CAB = 66°
<em>m∠CAD</em>
Given that is the diameter of the given circle, we have
The tangent, , is perpendicular to the radius of the circle, and therefore
is also perpendicular to the diameter of the circle
∴ m∠DAB = 90° which is the measure of the angle formed by two perpendicular lines
By angle addition property, we have;
m∠DAB = m∠CAB + m∠CAD
∴ m∠CAD = m∠DAB - m∠CAB
By substitution, we have;
m∠CAD = 90° - 66° = 24°
m∠CAD = 24°
we have given that
where represents the number of elements in C.
where we have 4 and 6 which have two elements.
so