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posledela
3 years ago
8

Can some help me plz.

Mathematics
1 answer:
vovikov84 [41]3 years ago
6 0
Wow I also go to that school
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PLEASE I NEED THIS TODAY!!!!
34kurt

Answer:

1/64 c

Step-by-step explanation:

.

7 0
3 years ago
Let f(x)=5(x^2-3)+10. which statement must be true?
Maslowich
Find where the expression
x
−
5
x
2
−
25
x
-
5
x
2
-
25
is undefined.
x
=
−
5
,
x
=
5
x
=
-
5
,
x
=
5
Since
x
−
5
x
2
−
25
x
-
5
x
2
-
25
→
→
−
∞
-
∞
as
x
x
→
→
−
5
-
5
from the left and
x
−
5
x
2
−
25
x
-
5
x
2
-
25
→
→
∞
∞
as
x
x
→
→
−
5
-
5
from the right, then
x
=
−
5
x
=
-
5
is a vertical asymptote.
x
=
−
5
x
=
-
5
Consider the rational function
R
(
x
)
=
a
x
n
b
x
m
R
(
x
)
=
a
x
n
b
x
m
where
n
n
is the degree of the numerator and
m
m
is the degree of the denominator.
1. If
n
<
m
n
<
m
, then the x-axis,
y
=
0
y
=
0
, is the horizontal asymptote.
2. If
n
=
m
n
=
m
, then the horizontal asymptote is the line
y
=
a
b
y
=
a
b
.
3. If
n
>
m
n
>
m
, then there is no horizontal asymptote (there is an oblique asymptote).
Find
n
n
and
m
m
.
n
=
1
n
=
1
m
=
2
m
=
2
Since
n
<
m
n
<
m
, the x-axis,
y
=
0
y
=
0
, is the horizontal asymptote.
y
=
0
y
=
0
There is no oblique asymptote because the degree of the numerator is less than or equal to the degree of the denominator.
No Oblique Asymptotes
This is the set of all asymptotes.
Vertical Asymptotes:
x
=
−
5
x
=
-
5
Horizontal Asymptotes:
y
=
0
y
=
0
No Oblique Asymptotes
5 0
3 years ago
PLEASE HELP MEEEEEEEE IM BEGGING
suter [353]
PLEASE HELP MEEEEEEEE IM BEGGING
4 0
3 years ago
Read 2 more answers
Towers A and B are located 10 miles apart. A ranger spots a fire at a 42-degree angle from tower A. Another fire ranger spots th
steposvetlana [31]

Answer:

7.0 mi

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the measure of angle C

Remember that the sum of the interior angles in any triangle must be equal to 180 degrees

so

A+B+C=180^o

substitute the given values

42^o+64^o+C=180^o

C=180^o-106^o=74^o

step 2

Find the measure of a

Applying the law of sines

\frac{c}{sin(C)}=\frac{a}{sin(A)}

substitute the given values

\frac{10}{sin(74^o)}=\frac{a}{sin(42^o)}

solve for a

a=\frac{10}{sin(74^o)}sin(42^o)

a=7.0\ mi

6 0
4 years ago
Read 2 more answers
Solve for g.<br> -3+5+6g=11-3g−3+5+6g=11−3g
PtichkaEL [24]

Answer: \mathrm{No\:Solution}

Step-by-step explanation:

\begin{bmatrix}-3+5+6g=1\\ 1-3g+5+6g=11-3g\end{bmatrix}

\begin{bmatrix}1-3\left(-\frac{1}{6}\right)+5+6\left(-\frac{1}{6}\right)=11-3\left(-\frac{1}{6}\right)\end{bmatrix}

\begin{bmatrix}\frac{11}{2}=\frac{23}{2}\end{bmatrix}

\frac{11}{2}=\frac{23}{2}\:\mathrm{\:is\:false,\:therefore\:the\:system\:of\:equations\:has\:no\:solution}

4 0
3 years ago
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