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4 years ago

Every even number,except 2,is composite

1 answer:

5 0

Yes. That's correct. Is that what you're asking...? To clarify, prime numbers have a single factor (one and itself) , composite numbers have multiple factors.

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A rectangular flying carpet is 1 1/2 m wide and 2 m long what is the area of the carpet

d1i1m1o1n [39]

Hi there! :)

Answer:

The area of the carpet is 3m².

Step-by-step explanation:

First off, the formula to calculate the area of a rectangle is this: A = L × W

Where "A" is the area, "L" the length and "W" the width.

Now that you have that, replace all the information you know in the equation in order to find the value of "A", which is what we are looking for:

- Just keep in mind that 1 1/2 is the same thing as 1.5

- The term "wide" is used to give the "width"

- The term "long" is used to give the "length"

A = L × W

A = 2 × 1.5

A = 3

There you go! I really hope this helped, if there's anything just let me know! :)

4 0

3 years ago

What is the answer for 1/7(1,000)

12345 [234]

1/7(1000) = 1/7(7000/7)

1*7000
7*7

7000
49

1000
7

so 1/7(1000) = 1000/7 or 142 6/7

5 0

3 years ago

Read 2 more answers

Required information Skip to question A die (six faces) has the number 1 painted on two of its faces, the number 2 painted on th

grigory [225]

Answer:

The change to the face 3 affects the value of P(Odd Number)

Step-by-step explanation:

Analysing the question one statement at a time.

Before the face with 3 is loaded to be twice likely to come up.

The sample space is:

$S = \{1,1,2,2,2,3\}$

And the probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{6}$

$P(1) = \frac{1}{3}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{6}$

$P(2) = \frac{1}{2}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{6}$

P(Odd Number) is then calculated as:

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{1}{3} + \frac{1}{6}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{6}$

$P(Odd\ Number) = \frac{3}{6}$

$P(Odd\ Number) = \frac{1}{2}$

After the face with 3 is loaded to be twice likely to come up.

The sample space becomes:

$S = \{1,1,2,2,2,3,3\}$

The probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{7}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{7}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{7}$

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{2}{7} + \frac{1}{7}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{7}$

$P(Odd\ Number) = \frac{3}{7}$

Comparing P(Odd Number) before and after

$P(Odd\ Number) = \frac{1}{2}$ --- Before

$P(Odd\ Number) = \frac{3}{7}$ --- After

We can conclude that the change to the face 3 affects the value of P(Odd Number)

7 0

3 years ago

22+9/4=? WILL MARK BRAINLIEST

Aleksandr-060686 [28]

The answer is 24.25 hope it helps

7 0

3 years ago

Is the sqrt of -36 a real number

Mkey [24]

Answer:

Step-by-step explanation:

The square root of any negative number is not a real number.

4 0

3 years ago

Read 2 more answers