Letter B is a function because all the x values are different. Letter C is a function also because even though the number 4 repeats, it is in the y value and not the x so as long as the x value’s are different, it is a function. Letter A is not a function because there are 2 of the same x values.
a. Find the probability that an individual distance is
greater than 214.30 cm
We find for the value of z score using the formula:
z = (x – u) / s
z = (214.30 – 205) / 8.3
z = 1.12
Since we are looking for x > 214.30 cm, we use the
right tailed test to find for P at z = 1.12 from the tables:
P = 0.1314
b. Find the probability that the mean for 20 randomly
selected distances is greater than 202.80 cm
We find for the value of z score using the formula:
z = (x – u) / s
z = (202.80 – 205) / 8.3
z = -0.265
Since we are looking for x > 202.80 cm, we use the
right tailed test to find for P at z = -0.265 from the tables:
P = 0.6045
c. Why can the normal distribution be used in part (b),
even though the sample size does not exceed 30?
I believe this is because we are given the population
standard deviation sigma rather than the sample standard deviation. So we can
use the z test.
A circle equals 360 degrees. There are 12, 5 minute sections on a clock. Divide 360 by 12 and you get 30.
If you move the hour hand backwards from 6 and move it to 2, you will move the hour hand 4 times.
Since 360/12=30, you will multiple 4 by 30, and you will get an answer of 120 degrees.
Here’s how it will look:
360/12=30
30*4=120 degrees
Answer:
a) 0.80
b) 0.72
c) 0.02
Step-by-step explanation:
It is assumed that
X = Bit transmitted
Y = Bit received
= Transmissted bit is 0
= Transmissted bit is 1
= Received bit is 0
= Received bit is 1
As per the given condition
P [ | ] = 90%
P [ | ] = 100% - 90% = 10%
P [ | ] = 74%
P [ | ] = 100% - 74% = 26%
P [ Tramitted bits are 0 ] = 80%
Now calculate each situation
a)
As all the transmitted bits are o has possibilit of 80% then
P [ X = 0 ] = P [ ] = 80% = 0.80
b)
P [ X = 0, Y = 0 ] = P [ , ] = P [ | ] x P [ ] = 90% x 80% = 72% = 0.72
c)
P [ X = 1, Y = 0 ] = P [ , ] = P [ | ] x P [ ] = 10% x ( 100% - 80% ) = 10% x 20% = 2% = 0.02
I remember being stuck on that question!
the answer is tan x