All categories

3 years ago

Find the length of side x in simplest radical form with a rational denominator

Mathematics

2 answers:

svetlana [45]3 years ago

5 0

Answer:

Step-by-step explanation:

fiasKO [112]3 years ago

4 0

Answer:

$\sqrt{6}$

Step-by-step explanation:

it is an isosceles triangle, so , x = $\sqrt{6}$

You might be interested in

6q-5q=7 <br> What does q equal?

Wittaler [7]

Answer: q=7

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

the u.s census bureau has a population clock on the Internet .on a recent day , the united states population Was listed as 310,7

Kamila [148]

Three hundred and ten million, seven hundred sixty-three thousand, one hundred and thirty-six

3 0

4 years ago

Find the nth term of this sequence : 7 , 12 , 17 , 22 , 27 ???

spayn [35]

32 is the answer and it is adding 5 everytime

4 0

3 years ago

Read 2 more answers

Can someone explain this differentiation question to me? I can differentiate but then I'm not sure what I am doing

weeeeeb [17]

note that gradient = $\frac{dy}{dx}$ at x = a

calculate $\frac{dy}{dx}$ for each pair of functions and compare gradient

(a)

$\frac{dy}{dx}$ = 2x and $\frac{dy}{dx}$ = - 1

at x = 4 : gradient = 8 and - 1 : 8 > - 1

(b)

$\frac{dy}{dx}$ = 2x + 3 and $\frac{dy}{dx}$ = - 2

at x = 2 : gradient = 7 and - 2 and 7 > - 2

(c)

$\frac{dy}{dx}$ = 4x + 13 and $\frac{dy}{dx}$ = 2

at x = - 7 : gradient = - 15 and 2 and 2 > - 15

(d)

$\frac{dy}{dx}$ = 6x - 5 and $\frac{dy}{dx}$ = 2x - 2

at x = - 1 : gradient = - 11 and - 4 and - 4 > - 11

(e)

y = √x = $x^{\frac{1}{2} }$

$\frac{dy}{dx}$ = 1/(2√x) and $\frac{dy}{dx}$ = 2

at x = 9 : gradient = $\frac{1}{6}$ and 2 and 2 > $\frac{1}{6}$

4 0

3 years ago

Prove the divisibility of the following numbers:

Brut [27]

Answer:

Step-by-step explanation:

To prove divisibility, we need to factor the divident such that one of its factors matches the divisor.

(I use the notation x|y to denote that x divides y)

(A)

$75^{30}|45^{45}\cdot15^{15}\\45^{45}\cdot15^{15}=3^{45}\cdot 15^{45}\cdot 15^{15}=\\=3^{45}\cdot 15^{60}=3^{45}\cdot 15^{30}\cdot 15^{30}=3^{45}\cdot (3\cdot5)^{30}\cdot 15^{30}=\\=3^{45}\cdot 3^{30}\cdot(5\cdot 15)^{30}=3^{45}\cdot 3^{30}\cdot(75)^{30}\\\implies\\75^{30}|3^{45}\cdot 3^{30}\cdot75^{30}$

(B)

$72^{63}|24^{54}\cdot 54^{24}\cdot2^{10}\\24^{54}\cdot 54^{24}\cdot2^{10}=(2^{162}\cdot 3^{54})\cdot(2^{24}\cdot 3^{72}) \cdot 2^{10}\\=2^{196}\cdot 3^{126}$

In this case, it is easier to also factor the divisor to primes:

$72^{63}=2^{189}\cdot 3^{126}$

Both of these factor must be matched in the dividend in order to prove divisibility, and that indeed turns out to be true:

$2^{189}\cdot 3^{126}|2^{196}\cdot 3^{126}\implies\\2^{189}|2^{196}\,\,\mbox{and}\,\,3^{126}|3^{126}$

6 0

3 years ago