All categories

3 years ago

I need help on this to please

Mathematics

1 answer:

vampirchik [111]3 years ago

7 0

Answer:

2,4

Step-by-step explanation:

because i said so

You might be interested in

Which expression represents the statement "the product of 3 less than a number and 5"}

yan [13]

Answer:

5(x-3)

Step-by-step explanation:

5 0

3 years ago

The comma after "however" should be removed

Nadya [2.5K]

Answer:

No it shouldent

Step-by-step explanation:

Because it needs a comma

Example...

Howether, jhon had 5

8 0

2 years ago

Mark thinks the equation y=6x+4 will match the red solid graph. Mia thinks it will match the blue dotted graph. Who’s right? Exp

Rudiy27

Answer:

Technically neither, but Mia is correct.

Step-by-step explanation:

Slope-Intercept Form: y = mx + b

Since our slope m is equal to 6, it is a positive number. That means that the slope/line will be positive, so the line should be going up, not down. That means the blue line would be correct. Therefore, Mia is correct.

Technicality:

Since the blue line is dotted, the equation should be a inequality and not a linear equation. No solutions on the line would technically work. If the equation was y < 6x + 4 or something with an inequality sign, then it would be correct.

6 0

3 years ago

8 + 8 hshshdhhdhfbfbcbcbcbcbcbbxbxbxbxbcbcbcb

Sidana [21]

Answer:

Step-by-step explanation:

8+8=16

6 0

3 years ago

Read 2 more answers

A teacher teaches two classes with 8 students each. Each student has a 95% chance of passing their class independent of the othe

dsp73

Answer:

0.4466 = 44.66% probability that, in exactly one of the two classes, all 8 students pass.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they pass, or they do not. The probability of an student passing is independent of other students, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Probability that all students pass in a class:

Class of 8 students, which means that $n = 8$

Each student has a 95% chance of passing their class independent of the other students, which means that $p = 0.95$

This probability is P(X = 8). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{8,8}.(0.95)^{8}.(0.05)^{0} = 0.6634$

Find the probability that, in exactly one of the two classes, all 8 students pass.

Two classes means that $n = 2$

0.6634 probability all students pass in a class, which means that $p = 0.6634$ .

This probability is P(X = 1). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{2,1}.(0.6634)^{1}.(0.3366)^{1} = 0.4466$

0.4466 = 44.66% probability that, in exactly one of the two classes, all 8 students pass.

3 0

3 years ago