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Sever21 [200]
3 years ago
14

Write the multiplicative inverse of 1.725. Enter your answer as a fraction in its simplest form. The multiplicative inverse of 1

.725 is
Mathematics
1 answer:
Katarina [22]3 years ago
8 0
Multiplicative inverse is a number which when multiplied with the current number, the answer unit (that is, 1).

Now,
1.725 = 1725/1000 = 69/40

Inverting this and multiplying it with the results yields 1. That is,

69/40*40/69 = 1
Therefore, the multiplicative inverse of 1.725 is 40/69
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8x+12-8x+15+15x-22-x
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3 years ago
What is the solution of the system of equations? -y+3x=6 y=-6x+12
irinina [24]

Answer:

x = 2

y = 0

Step-by-step explanation:

We can solve using substitution, substitute y in the first equation with the second equation:

-(-6x + 12) + 3x = 6

Distribute the negative sign:

6x - 12 + 3x = 6

Combine like terms:

9x - 12 = 6

Isolate the variable and solve for x by adding 12 in both sides:

9x = 18

x = 2

Substitute 2 with x in any equation to find the value of y:

-y + 3(2) = 6

-y + 6 = 6

Subtract 6 in both sides to isolate the variable:

-y = 0

0/-1 = 0

y = 0

Our answer would be x = 2 and y = 0

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Step-by-step explanation:

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2 years ago
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The general solution of 2 y ln(x)y' = (y^2 + 4)/x is
Sav [38]

Replace y' with \dfrac{\mathrm dy}{\mathrm dx} to see that this ODE is separable:

2y\ln x\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y^2+4}x\implies\dfrac{2y}{y^2+4}\,\mathrm dy=\dfrac{\mathrm dx}{x\ln x}

Integrate both sides; on the left, set u=y^2+4 so that \mathrm du=2y\,\mathrm dy; on the right, set v=\ln x so that \mathrm dv=\dfrac{\mathrm dx}x. Then

\displaystyle\int\frac{2y}{y^2+4}\,\mathrm dy=\int\dfrac{\mathrm dx}{x\ln x}\iff\int\frac{\mathrm du}u=\int\dfrac{\mathrm dv}v

\implies\ln|u|=\ln|v|+C

\implies\ln(y^2+4)=\ln|\ln x|+C

\implies y^2+4=e^{\ln|\ln x|+C}

\implies y^2=C|\ln x|-4

\implies y=\pm\sqrt{C|\ln x|-4}

4 0
2 years ago
Can someone help me ​
Nikolay [14]
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2 years ago
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