Answer:
f(x)=(x-1)^2+5 with domain x>1 and range y>5 has inverse g(x)=sqrt(x-5)+1 with domain x>5 and range y>1.
Step-by-step explanation:
The function is a parabola when graphed. It is in vertex form f(x)=a(x-h)^2+k where (h,k) is vertex and a tells us if it's reflected or not or if it's stretched. The thing we need to notice is the vertex because if we cut the graph with a vertical line here the curve will be one to one. So the vertex is (1,5). Let's restrict the domain so x >1.
* if x>1, then x-1>0.
* Also since the parabola opens up, then y>5.
So let's solve y=(x-1)^2+5 for x.
Subtract 5 on both sides:
y-5=(x-1)^2
Take square root of both sides:
Plus/minus sqrt(y-5)=x-1
We want x-1>0:
Sqrt(y-5)=x-1
Add 1 on both sides:
Sqrt(y-5)+1=x
Swap x and y:
Sqrt(x-5)+1=y
x>5
y>1
Associative Property if Addition
Answer:
c
Step-by-step explanation:
6 X 2 = 12 +5 = 17
Answer:
<u><em>1080</em></u> for the last one
Step-by-step explanation:
<em>40*12=480*2=960+120=</em><u><em>1080</em></u>
<em>12/4=3months 40*3=120</em>
The first one is 3
<em>1/2 + 1/4 = 3/4 </em>
<em>3/4 + 1/8 = 7/8</em>
<em>7/8 of 24 is 21</em>
<em>24-21= </em> <u><em>3</em></u>
A- they are parallel because they have equal slopes.
