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White raven [17]
3 years ago
5

How do you use an exponent to represent a number such as 81?

Mathematics
1 answer:
Mama L [17]3 years ago
8 0

Answer:

9²

Step-by-step explanation:

9 × 9 = 81

Nine to the power of Two

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Pls help with age problem.
kozerog [31]

Answer:

John is 19 and his sister is 23.

Step-by-step explanation:

See attached image.

3 0
2 years ago
Aflati al 2013 lea termen al unei progresii aritmetice cu termenul al treilea egal cu 12 si diferenta a doi termeni consecutivi,
KATRIN_1 [288]

Răspuns:

8052

Explicație pas cu pas:

Al treilea termen al unei progresii aritmetice:

T (n) = a + (n - 1) d

Unde ;

a = primul termen; d = diferență comună = 4; n = al treilea termen (numărul termenului)

Al treilea (3) termen:

T (3) = a + (3-1) 4

T (3) = 12

12 = a + 2 (4)

12 = a + 8

12 - 8 = a

4 = a

Prin urmare, primul termen = a

Al 2013-lea mandat;

T (2013) = a + (2013-1) d

T (2013) = 4 + (2012) 4

T (2013) = 4 + 8048

= 8052

4 0
3 years ago
Find the value of x in the equation below. 3x = 18
Oxana [17]

Answer:

x=6

Step-by-step explanation:

you need to get x alone so you divide by 3 on both sides

hope this helps!!! :)

example:

3x/3= 18/3

x=6

4 0
3 years ago
Read 2 more answers
Orbet used 24 square tiles to make a rectangle. The perimeter of the rectangle is 20 units. What would be the perimeters of the
Dmitriy789 [7]

Answer:

The perimeter of other rectangles are 50, 28, 22 units

The area of all possible rectangles are same and equals to 24 unit²

Step-by-step explanation:

Given - Orbet used 24 square tiles to make a rectangle. The perimeter of the rectangle is 20 units.

To find -  What would be the perimeters of the other rectangles Orbet could make using only these 24 tiles? How do the areas of the rectangles compare?

Proof -

We know that

Are of Rectangle = Length × Breadth

And Perimeter of Rectangle = 2 (Length + Breadth )

Now,

Given that,

Orbet used 24 square tiles

And perimeter of the rectangle made = 20

So,

Possible Length of rectangle = 6

Possible breadth of Rectangle = 4

Or Vice-versa.

Total number of Rectangles possible = 4

Possibilities are -  1 × 24, 2 × 12, 3 × 8, 4 × 6

Case I :

Length of rectangle = 1

Breadth of rectangle = 24

∴ Perimeter of rectangle = 2(1 + 24) = 2(25) = 50 units

Area of rectangle = 1 × 24 = 24 unit²

Case II :

Length of rectangle = 2

Breadth of rectangle = 12

∴ Perimeter of rectangle = 2(2 + 12) = 2(14) = 28 units

Area of rectangle = 2 × 12 = 24 unit²

Case III :

Length of rectangle = 3

Breadth of rectangle = 8

∴ Perimeter of rectangle = 2(3 + 8) = 2(11) = 22 units

Area of rectangle = 3 × 8 = 24 unit²

Case IV :

Length of rectangle = 4

Breadth of rectangle = 6

∴ Perimeter of rectangle = 2(4 + 6) = 2(10) = 20 units

Area of rectangle = 4 × 6 = 24 unit²

∴ we get

The perimeter of other rectangles are 50, 28, 22 units

The area of all possible rectangles are same and equals to 24 unit²

5 0
3 years ago
How do i solve 2x-y=9
devlian [24]
20 with a number minus what will equal 9. ^_^
3 0
4 years ago
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