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3 years ago

5

Find the quotient:

0552 \div 12" align="absmiddle" class="latex-formula">

1 answer:

Oksana_A [137]3 years ago

7 0

2.004583333333333 is the answer

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Proof that :<br><img src="https://tex.z-dn.net/?f=%20%7Bsin%7D%5E%7B2%7D%20%5Ctheta%20%2B%20%20%7Bcos%7D%5E%7B2%7D%20%5C%3A%5Cth

Arisa [49]

Answer:

Solution given:

Right angled triangle ABC is drawn where <C= $\theta$

we know that

$\displaystyle Sin\theta=\frac{opposite}{hypotenuse} =\frac{AB}{AC}$

$\displaystyle Cos\theta=\frac{adjacent}{hypotenuse}=\frac{BC}{AC}$

Now

left hand side

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distributing power

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Taking L.C.M

$\displaystyle \frac{AB²+BC²}{AC²}$ ....[I]

In ∆ABC By using Pythagoras law we get

$\boxed{\green{\bold{Opposite²+adjacent²=hypotenuse²}}}$

AB²+BC²=AC²

Substituting value of AB²+BC² in equation [I]

we get

$\displaystyle \frac{AC²}{AC²}$

=1

Right hand side

<h3><u>proved</u></h3>

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Step-by-step explanation:

i kinda remember i think

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