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Tamiku [17]
3 years ago
5

Find the quotient:

0552 \div 12" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
Oksana_A [137]3 years ago
7 0
2.004583333333333 is the answer
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perimeter of parallelogram 140 cm if one side is longer than the other by 10cm, find the length of each of its parallel side
Verizon [17]

The length of each of its parallel side are 30 cm and 40 cm.

<u>Step-by-step explanation</u>:

  • Perimeter of parallelogram = 140 cm.
  • The one side of parallelogram = x cm.
  • The other side of parallelogram = x+10 cm.

Perimeter of a parallelogram = 2 (base+height)

⇒ 140 = 2(x+x+10)

⇒ 140 = 2(2x+10)

⇒ 140 = 4x+20

⇒ 4x = 120

⇒ x = 120/4

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4 years ago
2<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%2B5%7D%2B4%5C%5C" id="TexFormula1" title="\sqrt{x+5}+4\\" alt="\sqrt{x+5}+4\\" al
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2 \sqrt{x + 9}

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Please help find domain and range
Oxana [17]
<h3>Answer:  Choice A</h3>
  • Domain:  x > 4
  • Range: y > 0

========================================================

Explanation:

We want to avoid having a negative number under the square root. Solving x-4 \ge 0 leads to x \ge 4

So it appears the domain could involve x = 4 itself; however, if we tried that x value, then we'd get a division by zero error.

So in reality, the domain is x > 4.

-------------

The range of y = sqrt(x) is the set of positive real numbers. So y > 0 is the range for this equation. Shifting left and right does not affect the range, so the range of y = sqrt(x-4) is also y > 0.

We are dividing a positive number (3) over some positive number in the denominator. Overall, the expression \frac{3}{\sqrt{x-4}} is positive because positive/positive = positive.

Therefore, the range of the given equation is y > 0

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The graph is shown below. We have a vertical asymptote at x = 4 and a horizontal asymptote at y = 0. The green curve is fenced in the upper right corner (northeast corner).

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dimulka [17.4K]
The 56th term in the sequence is 195
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