Answer:
404 cm³ Anyway... Look down here for my explanation.
Step-by-step explanation:
Let's Draw a line from the center of the circle to one of the ends of the chord (water surface) and another to the point at greatest depth on your paper. A right-angled triangle is formed too. The Length of side to the water-surface is 5 cm, the hospot is 7 cm.
We Calculate the angle θ in the corner of the right-angled triangle by: cos θ = 5/7 ⇒ θ = cos ˉ¹ (5/7)
44.4°, so the angle subtended at the center of the circle by the water surface is roughly 88.8°
The area shaded will then be the area of the sector minus the area of the triangle above the water in your diagram.
Shaded area 88.8/360*area of circle - ½*7*788.8°
= 88.8/360*π*7² - 24.5*sin 88.8°
13.5 cm²
(using area of ∆ = ½.a.b.sin C for the triangle)
Volume of water = cross-sectional area * length
13.5 * 30 cm³
404 cm³
9. 1/3+(x+20)+(x-10)+40=360 10. 1/2x+1/2x+(x-15)+(x-25)+100=540
1/3+2x+50=360 4x+60=540
(3/1) 1/3+2x=300(3/1) 4x/4=480/4
2x=300 X=120
————
2
W=150
Omg I’m so sorry I’m not giving you your answer but I need to comments so I can post my questions hope you get your answer!
If we dialate a function we are just changing what the graph looks like by a stretch or a compression, the function really doesn't change. If a function before the dilation, then it is a function after the dilation. The opposite is also true.
