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Basile [38]
3 years ago
10

PLZ ANSWER THIS thanksssss

Mathematics
1 answer:
just olya [345]3 years ago
5 0

Answer:

It should be C) 11+ 3 5/8

Step-by-step explanation:

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Which equation represents the hyperbola in general form?
valina [46]

ANSWER

D.

9 {y}^{2}  - 4 {x}^{2}- 36y + 16x - 16 = 0

EXPLANATION

The standard equation of the hyperbola is

\frac{ {(y - 2)}^{2} }{4}  -  \frac{ {(x - 2)}^{2} }{9}  = 1

We multiply through by 36 to obtain:

9 {(y - 2)}^{2}  - 4( {x - 2)}^{2}  = 36

We now expand to get,

9( {y}^{2}  - 4y + 4) - 4( {x}^{2}  - 4x + 4) = 36

Expand :

9 {y}^{2}  - 36y + 36  - 4 {x}^{2}  + 16x - 16 = 36

To get the general form, we equate everything to zero to get,

9 {y}^{2}  - 4 {x}^{2}- 36y + 16x - 16 = 0

The correct choice is D.

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3 years ago
Complete this sentence: in a triangle, the angle with the smallest measure is always opposite the
Marta_Voda [28]

Answer:

Complete this sentence: in a triangle, the angle with the smallest measure is always opposite the <u><em>shortest side</em></u>.

8 0
3 years ago
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What is 4 1/12 equivalent to?
marusya05 [52]
9/2 or 4.5

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4 years ago
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This map shows the location of mice in the maze.
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On point (5,1) Fam......................
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A person traveling from Seattle to Sydney has three airlines to choose from. 40% of travelers choose airline A, and this airline
dalvyx [7]

Answer:

46.67% probability that they flew with airline B.

Step-by-step explanation:

We have these following probabilities:

A 40% probability that a traveler chooses airline A.

A 35% probability that a traveled chooses airline B.

A 25% probability that a traveler chooses airline C.

If a passenger chooses airline A, a 10% probability that he arrives late.

If a passenger chooses airline B, a 15% probability that he arrives late.

If a passenger chooses airline C, a 8% probability that he arrives late.

If a randomly selected traveler is on a flight from Seattle which arrives late to Sydney, what is the probability that they flew with airline B?

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

So

What is the probability that the traveler flew with airline B, given that he was late?

P(B) is the probability that he flew with airline B.

So P(B) = 0.35

P(A/B) is the probability of being late when traveling with airline B. So P(A/B) = 0.15.

P(A) is the probability of being late. This is the sum of 10% of 40%(airline A), 15% of 35%(airline B) and 8% of 25%(airline C).

So

P(A) = 0.1*0.4 + 0.15*0.35 + 0.08*0.25 = 0.1125

Probability

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.35*0.15}{0.1125} = 0.4667

46.67% probability that they flew with airline B.

5 0
3 years ago
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