Answer:
(-9/7,-26/7)
[more detailed at the bottom of the explanation]
Step-by-step explanation:
I am assuming that this is a system of equations...
So, knowing that y is equal to x + 5, you would plug that in the second equation and find x. Then you would plug x and find y.
—————
Step 1)
Equation 1:
y = (x + 5)
Equation 2:
5x + 2y = 1
Equation 2 can also be written as:
5x + 2(x+5) = 1
I wrote x+5 instead of y because the first equation tells us that y is equal to x + 5.
—————
Step 2)
Solve for x .
5x + 2(x+5) = 1
5x + 2x + 10 = 1
7x + 10 = 1
7x = 1 - 10
7x = -9
x = -9/7
—————
Step 3)
Plug the x value back in the first equation.
y = -9/7 + 5
y = -26/7
—————
Solution:
x = -9/7
y = -26/7
In ordered pair form:
(-9/7,-26/7)
————— ————— —————
Hope this helps !!!!!!!
The length would be w+4 since it is 4 inches more than the width, which is w.
You times the denominator from 2/3 by 4 so it can be equivalent to 8/12
2/3 x 4 = 8/12-8/12=0
9514 1404 393
Answer:
f(x) = -1/2x +1
Step-by-step explanation:
The line crosses the y-axis at y=1, so the y-intercept is b=1.
The line drops 1 unit for a run of 2 to the right, so the slope is ...
m = rise/run = -1/2
The slope-intercept form of the equation of the line is ...
y = mx + b
y = -1/2x + 1
In functional form, the equation is ...
f(x) = -1/2x +1
Answer:
t=5.5080( to 3 d.p)
Step-by-step explanation:
From the data given,
n =20
Deviation= 34/20= 1.7
Standard deviation (sd)= 1.3803(√Deviation)
Standard Error = sd/√n
= 1.3803/V20 = 0.3086
Test statistic is:
t = deviation /SE
= 1.7/0.3086 = 5.5080
ndf = 20 - 1 = 19
alpha = 0.01
One Tailed - Right Side Test
From Table, critical value of t =2.5395
Since the calculated value of t = 5.5080 is greater than critical value of t = 2.5395, the difference is significant. Reject null hypothesis.
t score = 5.5080
ndf = 19
One Tail - Right side Test
By Technology, p - value = 0.000
Since p - value is less than alpha , reject null hypothesis.
Conclusion:
From the result obtained it can be concluded that ,the data support the claim that the mean rating assigned to the wine when the cost is described as $90 is greater than the mean rating assigned to the wine when the cost is described as $10.
