Answer:
Explanation:
D)The system is open, and the net external force is nonzero.
The mass of hydrogen in 57.010 g ammonium hydrogen phosphate, (NH₄)H₂PO₄ is 2.97 g
<h3>Determination of mass of 1 mole of (NH₄)H₂PO₄ </h3>
1 mole of (NH₄)H₂PO₄ = 14 + (4×1) + (2×1) + 31 + (16×4) = 115 g
<h3>Determination of the mass of H in 1 mole of (NH₄)H₂PO₄ </h3>
Mass of H = 6H = 6 × 1 = 6 g
<h3>Determination of the mass of H in 57.010 g of (NH₄)H₂PO₄ </h3>
115 g of (NH₄)H₂PO₄ contains 6 g of H.
Therefore,
57.010 g of (NH₄)H₂PO₄ will contain = (57.010 × 6) / 115 = 2.97 g of H
Thus, 2.97 g of Hydrogen, H is present in 57.010 g of (NH₄)H₂PO₄
Learn more about mass composition:
brainly.com/question/13531044
The Complex nth Roots Theorem with any nonzero complex number has exactly n ∈ N distinct nth roots.
<h3>
What is a non-zero complex number?</h3>
This is the quantity which does not equal zero is said to be nonzero. A real nonzero number must be either positive or negative, and a complex nonzero number can have either real or imaginary part nonzero.
The roots lie on a circle of radius centered at the origin and spaced out evenly by angles of 2π/n.
Learn more about the <em>nth root</em> here:
brainly.com/question/1581238
