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azamat
3 years ago
11

When you are sitting on the couch reviewing in your own mind all of your thoughts and feelings experienced throughout the day, y

ou are engaging in quizlet
SAT
1 answer:
trasher [3.6K]3 years ago
6 0

The correct answer to this open question is the following.

Although there are no options attached, we can say the following.

When you are sitting on the couch reviewing in your own mind all of your thoughts and feelings experienced throughout the day, you are engaging in psychotherapy.

When you, as the patient, are in a psychotherapy session, this means that the expert psychologist proceeds with a series of questions and comments that help you to start talking about your problems. These procedures are validated by science and are designed to resolve your problems. You have to be calm and relaxed to maximize the results of the therapy. That is why part of the technique is that you are sitting on the couch reviewing in your own mind all of your thoughts and feelings.

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Notices for files:
azamat

Answer:

Umm Okay

Explanation:

5 0
3 years ago
ENERGÍA ALTERNATIVA
yan [13]

Answer:

hola, amigo, no estoy seguro de haber hablado americano, pero ¿es 4

Explanation:

5 0
3 years ago
*SAT QUESTION*
mars1129 [50]

Answer:

The answer is Option A

Explanation:

Cup of milk m = 299 mg

Cup of juice j = 261 mg

Limit of intake = 1000mg

Total amount of calcium from milk = 299 × m = 299m mg

Total amount of calcium from juice = 261 × j = 261j mg

Since it must be equal to or exceeding the daily limit u use the GREATER THAN OR EQUAL TO SIGN.

299m + 261j <u>></u> 1000

4 0
3 years ago
Read 2 more answers
A 0. 75-kg ball is attached to a 1. 0-m rope and whirled in a vertical circle. The rope will break when the tension exceeds 450
8090 [49]

At the bottom of the circle, the ball is being pulled upward by tension in the rope and downward by its own weight, so that the net force on it is

∑ F = 450 N - (0.75 kg) g = (0.75 kg) a

where a is centripetal acceleration. At this maximum tension, the ball has a maximum centripetal acceleration of

a = (450 N - (0.75 kg) g) / (0.75 kg) = 590.2 m/s²

Then its maximum tangential speed v is such that

a = v² / (1.0 m)

⇒   v = √((1.0 m) a) ≈ 25 m/s

7 0
2 years ago
37 cos(x2) dx 0 Do the following. (a) Find the approximations T8 and M8 for the given integral. (Round your answer to six decima
dusya [7]

The approximations T8 and M8 for the given integral are:

  • T8 = 33.386321; and
  • M8 = 33.50794

<h3>What is an integral?</h3>

An Integral is a variable of which a given function is the derivative, i.e. it gives that function when differentiated and may express the area under the curve of the function's graph.

<h3>What is the explanation to above answer?</h3>

Given:

F(x) = 37 cox (x²)

Internal = [0,1] n = 8 in Δ x = 1/8

The sub intervals are:

[0, 1/8], [1/8, 2/8], [2/8, 3/8], [ 3/8, 4/8], [ 4/8, 5/8], [ 5/8, 6/8], [6/8, 7/8], [ 7/8, 1]

The mid points are given as:

1/16, 3/16, 5/16, 7/16, 9/16, 11/16, 13/16, 15/16

and X₀ = 0, X₁ = 1/8, X₂ = 2/8

Using the Trapezium Rule which states that:

\int\limits^1_0 cos(x)^{2} } \, dx = Δx/2 [f(xo) + 2f(x1) 2f(x2) + ....+ 2f(x7) + f(x8)]

= 1/1Q[f(0) + 2f (1/8) + 2f(2/8) + ....+ 2f(7/8) + f(1)]

= 0.902333

Now

T8 = \int\limits^1_0 {37Cos(x)^{2} } \, dx

= 37\int\limits^1_0 {(0.902333)} } \, dx

= 37 (0.902333)

T8 = 33.386321

It is to be noted that the midpoints rule is given as;

\int\limits^1_0 {Cos(x)^{2} } \, dx  = Δx [f(1/16) + (3/16) + .... + f(15/16)]

= 1/8[f(1/16) + f (3/16) + f(5/16) + f(7/16) + f(9/16) + f(11/16) + f(13/16) + f(15/16)]

= 0.905620

From the above,

M8 = \int\limits^1_0 {37 Cos(x)^{2} } \, dx

= 37\int\limits^1_0 {Cos(x)^{2} } \, dx

= 37 (0.905620)

M8 = 33.50794

Learn more about integral at;
brainly.com/question/19053586
#SPJ1

6 0
2 years ago
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