(For full answer you might have to go to the comments)
Answer: 28x+30
Explanation: we divide (3x^3-2x^2+4x-3) by (x^2+3x+3) Using long division
3x-11
___________________
(x^2+3x+3) 3x^3-2x^2+4x-3
-(3x^3+9x^2+9x)
__________________
-11x^2-5x-3
-(-11x^2-33x-33)
____________
28x+30
So our remainder will be 28x+30
First no. = x
Second no. = y
Equation Formation
x + y = 6..........equation(i)
x - y = 10...........equation (ii)
x = 6 - y
6 - y - y = 10
6 - 2 y = 10
-2 y = 10 -6
-2 y = 4
y = -2
x = 6 + 2
x = 8
Answer = 8 , -2
Answer:
x^0 y^-3 / x^2 y^-1
= 1 / x^2 y^-1 (y^3) ...because x^0 = 1 and [(y^-1) (y^3)] = y^2
= 1/(x^2 y^2)
Answer: b is the answer
Step-by-step explanation:
Answer:
b = 94/79
Step-by-step explanation:
47/79 = x/2
79x = 94
x = 94/79