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Agata [3.3K]
2 years ago
14

HELP PLS!!!! SOLVE ALGEBRA

Mathematics
1 answer:
Firdavs [7]2 years ago
3 0

Answer:

#11) D) x<0 or x≥7

Step-by-step explanation:

Hope this helps

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The coordinates of the vertices if JKL are J(0,2),K(3,1),And K(1,-5)
Anika [276]

Answer:

K(3,1),And K(1,-5),j(0,2) t

Step-by-step explanation:


7 0
3 years ago
(x + 7)^2 – 11 = 0<br> lesser =<br> greater =
Andreyy89

Answer:

Lesser = -\sqrt{11} - 7 = -10.317

Greater = +\sqrt{11} - 7 = -3.683

Step-by-step explanation:

I am assuming you are asking for the lesser x solution and greater x solution.

(x + 7)^2 – 11 = 0

(x + 7)^2 = 11

x+7 = ±\sqrt{11}

x = ±\sqrt{11} - 7

Lesser = -\sqrt{11} - 7 = -10.317

Greater = +\sqrt{11} - 7 = -3.683

4 0
3 years ago
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What is the square root of 49.<br> a. 7<br> a.<br> b. 6<br> C. 8<br> 2 d. 9
Mashcka [7]

Answer:

a. 7

Step-by-step explanation:

7x7=49

6 0
3 years ago
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Consider this system of equations.  x + 2y = 5,  –x + 3y = 6 The x- and y-intercepts of the first equation are found below. x-in
vichka [17]

Answer:

Part 1) The x-intercept is the point (-6,0)

Part 2) The y-intercept is the point (0,2)

Step-by-step explanation:

we know that

The x-intercept is the value of x when the value of y is equal to zero

The y-intercept is the value of y when the value of x is equal to zero

we have

-x+3y=6

Part 1) Find the x-intercept

For y=0

substitute the value of y in the linear equation and solve for x

-x+3(0)=6

-x=6

x=-6

The x-intercept is the point (-6,0)

Part 2) Find the y-intercept

For x=0

substitute the value of x in the linear equation and solve for y

-(0)+3y=6

3y=6

y=2

The y-intercept is the point (0,2)

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3 years ago
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borishaifa [10]
The runner ran 5/6 then he ran 9/10 more how much did he run in all
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3 years ago
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