The answer is
<span>A. 12x2 + 6x
solution
</span><span>y = 4x3 + 3x2 + 2
</span><span>y'(x) = 12x^2 + 6x
</span>
X=3.8
Sin41/2.5 = sin90/x
Sin90 x 2.5 = sin41 x X
Sin90 x 2.5/ sin41
X=3.8
X²-9x=36
minus 36 both sides
x²-9x-36=0
what 2 numbers multiply to -36 and add to -9
-12 and 3
(x-12)(x+3)=0
set to zero
x-12=0
x=12
x+3=0
x=-3
the number is either -3 or 12
Answer:
t=16
Step-by-step explanation:
you have to change the numbers to get just the variable.
we start from -3.
5=t/2-3
8=t/2
(we multiply by 2 instead of dividing)
8×2=16
t=16
