3 years ago

Help answer this question pls

Mathematics

1 answer:

Marina86 [1]3 years ago

6 0

Answer:

a. only 21 males drink only coffee

b. 21/100

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I'm having trouble with this, it's geometry. please help and break it down if you can

Travka [436]

Check the picture below.

5 0

3 years ago

Amanda only has $30 to buy pens and notebooks. Each pen costs $2. Each notebook coats $3. Which of the following graph represent

sineoko [7]

Answer:

3p + 8n, 12p + 2n, 9p+4n, 6p+6n

8 columns bar graph.

Step-by-step explanation:

$2 = pen

$3 = notebook

This could be written as a bar graph in multiples of $6.00 along y axes.

3 pens + 8 notebooks. Then 12 pens + 2 notebooks.

Then 9 pens + 4 notebooks . Then 6 pens + 6 notebooks

3p + 8n, 12p + 2n, 9p+4n, 6p + 6n

3p = $6

8n = $24

12p = $24

2n = $6

9p = $18

4n = $12

6p = $12

6n = $18

and so on...

4 0

2 years ago

What is the volume of a rectangular prism that is 3 cm by 7 cm by by 7 cm?

natali 33 [55]

Answer:

147 $cm^{3}$

Step-by-step explanation:

7*7*3 = 147

volume of a rectangular prism = length*width*height, in this case, 7*7*3

hope this helps :)

3 0

3 years ago

Sam has 15 identical rectangular windows in his home. The length of each window is twice the width, and the area of each window

marshall27 [118]

The answe would be 300 because, the perimeter of the windows is 12, then you have to multiply 25 to 12 then bam you get 300, yay!

5 0

3 years ago

A limited-edition poster increases in value each year with an initial value of $18. After 1 year and an increase of 15% per year

Roman55 [17]

Answer:

The required equation is $y = 18(1.15)^x$ .

Step-by-step explanation:

Consider the provided information.

The Initial value of poster = $ 18

After 1 year amount of increase = $ 20.70

With the rate of 15% = 0.15

Let future value is y and the number of years be x.

$y = 18(1.15)^x$

Now verify this by substituting x=1 in above equation.

$y = 18(1.15)^1=20.7$

Which is true.

Hence, the required equation is $y = 18(1.15)^x$ .

7 0

3 years ago

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