A crop scientist is conducting research with a drought resistant corn hybrid. She is interested in determining if increasing the
spacing between these plants will increase yield. She prepares 30 single acre plots and randomly assigns 15 to have normal spacing while the other 15 are planted with an expanded spacing. The resulting average yield for each group of 15 plots was recorded. Select all that apply.
Select one or more:
a. The explanatory variable is whether the corn plants had normal spacing or expanded spacing.
b. The response variable is the yield of the crops.
c. The explanatory variable is the yield of the crops.
d. The response variable is whether the corn plants had normal spacing or expanded spacing.
e. This study is best described as an experiment.
f. This is best described as an observational study.
the scientist can control and deal with the measure of manure that is given to a solitary corn plants. thus A is correct.
The reaction variable is the yield recorded for each plot due to the fact that the yield recorded in each plot is needed to check whether the compost is given or not. choice B is also correct
it's considered an experiment because the specialist is controlling the autonomous variable. then E is a right choice.
Solve for the first variable in one of the equations, then substitute the result into the other equation. Point Form: ( 8 , − 3 ) Equation Form: x = 8 , y = − 3
You use pi times radius squared. Pi 15 squared=706.858 then take 706.858 and multiply it by the depth of 12. 706.858×12=8482.3 Cm squared. 8482.3 cm to liters is about 8.5 liters
