K=4(5)
k=20
you just plug in 5 for d and multiply normally from there.
If you want to find cosP , since angles Z and P are 2 complementary angles then cosZ is the same as cosP so you say the cosP=sinZ=4/5 (property of 2 complement angles in a right triangle)
Direct variation should be called linear variation.
In this case, the answer is B.
A has the quadratic variation, C has the inverse variation, D has the cubic variation
Slope y-intercept form is: y=mx+b
All you have to do is rearrange the equation:
2x-3y=6
2x=6+3y
2x-6=3y
now divide both sides by 3
(2x/3)-(6/3)=(3y/3)
and it becomes

x
Bonus: you can plug in any two values for x and y and you can see both equation gives the same answer!
Answer:
The correct answer is option C
(f o g)(x) = 3x² + 7x + 2
Step-by-step explanation:
<u>Points to remember</u>
<u>Composite functions</u>
Let f(x) and g(x) be the two functions then (f o g)(x) can be written as
(f o g)(x) = f(g(x))
<u>To find the value of (f o g)(x)</u>
Here f(x) =x + 2 and g(x) = 3x² + 7x
(f o g)(x) = f(g(x))
= f(3x² + 7x)
= 3x² + 7x + 2
Therefore the correct answer is option C
(f o g)(x) = 3x² + 7x + 2