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3 years ago

5

ANSWER PLSSS!! Brian puts $2000 in the bank. He leaves it there for 2 years. The bank uses an interest rate of 4%. How much mone

y would Brian have in the bank after the 2 years.

1 answer:

irinina [24]3 years ago

3 0

Answer:

the answer is $1920

Step-by-step explanation:

4% of $2000 is $80 so if they take 4% its just $2000 - $80 = $1920

Hope this helped! <3

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Which conversion factors are used to convert 12 m/s to kilometers per minute?

Lera25 [3.4K]

Answer:

see the procedure

Step-by-step explanation:

we have

$12\ \frac{m}{s}$

Remember that

$1\ km=1,000\ m$

To convert m to km multiply by (1/1,000)

$1\ min=60\ sec$

To convert sec to min multiply by (1/60)

substitute

$12\ (\frac{(1/1,000)}{(1/60)})=12(\frac{60}{1,000})=0.72\ \frac{km}{min}$

7 0

2 years ago

If the expression $3^1 times 9^2 times 27^3 \times 81^4 is simplified to the form 3^n, what is the value of n?

Darina [25.2K]

Answer:

$n=30$

Step-by-step explanation:

Given expression:

$3^1\times 9^2\times 27^3\times 81^4$

The given expression needs to be simplified to the form $3^n$

Applying the exponents rule to simplify.

$3^1\times 9^2\times 27^3\times 81^4$

Writing all numbers as product of 3.

⇒ $3^1\times (3\times3)^2\times (3\times3\times3)^3\times (3\times3\times3\times3)^4$

Writing each in exponents form.

⇒ $3^1\times (3^2)^2\times (3^3)^3\times (3^4)^4$

Using power of a power rule $[\ (a^x)^y=a^{xy}\ ]$

⇒ $3^1\times 3^4\times 3^9\times 3^16$

Using multiplication rule of exponents $[\ a^x\times a^y=a^{x+y}\ ]$

⇒ $3^{1+4+9+16}$

⇒ $3^{30}$

So we have $3^n=3^{30}$

∴ $n=30$

8 0

2 years ago

Starting at the same point at the same time, Samuel and Heather rode their bikes in the same direction. Samuel traveled 3km/h fa

12345 [234]

Samuel was going with 40 km/h and Heather was going with 37 km/h

Step-by-step explanation:

Starting at the same point at the same time, Samuel and Heather rode their bikes in the same direction

Samuel traveled 3 km/h faster than Heather
After 3.5 h Samuel stopped for a half-hour break, but Heather kept going
Heather was 8 km ahead of Samuel

We need to find how fast each was going

Assume that Heather's speed is x km/h

∵ Heather's speed = x km/h

∵ Samuel traveled 3 km/h faster than Heather

∴ Samuel's speed = x + 3 km/h

The formula of the distance is distance = speed × time

∵ Samuel travel for 3.5 hours

- Find the distance that Samuel traveled in 3.5 h

∴ Samuel distance = (x + 3) × 3.5

- Multiply the bracket by 3.5 to simplify

∴ Samuel distance = 3.5x + 10.5

∵ Samuel took a break for half hour

∵ Heather kept going

∵ At the end of the break, Heather was 8 km ahead of Samuel

- That means Heather was going for 4 hours (3.5 + 0.5), and her

distance is longer than Samuel distance by 8 km

∴ Heather distance = x × 4 = 4x

- Subtract the distance of Samuel from the distance of Heather

and equate the difference by 8

∵ 4x - (3x + 10.5) = 8

∴ 4x - 3x - 10.5 = 8

- Add the like terms in the left hand side

∴ 0.5x - 10.5 = 8

- Add 10.5 to both sides

∴ 0.5x = 18.5

- Divide both sides by 0.5

∴ x = 37

∵ x represents Heather's speed

∴ Heather's speed = 37 km/h

∵ x + 3 represents Samuel's speed

∴ Samuel's speed = 37 + 3 = 40 km/h

Samuel was going with 40 km/h and Heather was going with 37 km/h

Learn more:

You can learn more about the equation of motion in brainly.com/question/568302

#LearnwithBrainly

3 0

3 years ago

Klein read 30 pages of a book on Monday and 1/8 of the book on Tuesday. He completed the 1/4 of the book on Wednesday. How many

ozzi

The answer would be 33 3/8

6 0

2 years ago

If the function h is defined by h(x)=<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" a

harkovskaia [24]

Given:

The function is:

$h(x)=x^2-3x+5$

To find:

The value of $h(2x+1)$ .

Solution:

We have,

$h(x)=x^2-3x+5$

Putting $x=2x+1$ , we get

$h(2x+1)=(2x+1)^2-3(2x+1)+5$

$h(2x+1)=(2x)^2+2(2x)(1)+(1)^2-3(2x)-3(1)+5$

$h(2x+1)=4x^2+4x+1-6x-3+5$

On combining like terms, we get

$h(2x+1)=4x^2+(4x-6x)+(1-3+5)$

$h(2x+1)=4x^2-2x+3$

Therefore, the required function is $h(2x+1)=4x^2-2x+3$ .

3 0

3 years ago