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postnew [5]
3 years ago
5

ANSWER PLSSS!! Brian puts $2000 in the bank. He leaves it there for 2 years. The bank uses an interest rate of 4%. How much mone

y would Brian have in the bank after the 2 years.
Mathematics
1 answer:
irinina [24]3 years ago
3 0

Answer:

the answer is $1920

Step-by-step explanation:

4% of $2000 is $80 so if they take 4% its just $2000 - $80 = $1920

Hope this helped! <3

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Will the Brainliest answer!!!<br><br> solve for x and y.<br><br> 946x+642y=911
Ronch [10]

While you cannot solve 946x+642y=911 for numerical values of x and y, you can indeed solve 946x+642y=911 first for x and then for y:

-911 - 642y

For x: 946x+642y=911 becomes 946x = 911 - 642y, or x = ------------------

946

911-946x

For y: 946x+642y=911 becomes 642y = 911-946x, or y = ---------------

642

8 0
4 years ago
Read 2 more answers
Chris is working on a stained-glass project and needs to form a triangle with sides of 8, 12, and 15 inches out of lead cane to
Slav-nsk [51]

Answer:

The largest angle needed is 95.1^{o}.

Step-by-step explanation:

To determine the larges angle as required, let us apply the cosine rule.

c^{2} = a^{2} + b^{2} - 2ab Cos C

Since in triangles, the longest side is opposite to the largest angle, then;

15^{2} = 8^{2} + 12^{2} - 2(8 x 12) Cos θ

225 = 64 + 144 - 192 Cos θ

225 = 208 - 192 Cos θ

192 Cos θ = 208 -225

192 Cos θ = -17

Cos θ = \frac{-17}{192}

Cos θ = -0.08854

θ = Cos^{-1} -0.08854

  = 95.07962

θ = 95.1^{o}

The largest angle needed is 95.1^{o}.

3 0
3 years ago
A farmer in China discovers a mammal hide that contains 37% of its original amount of C-14. Find the age of the mammal hide to t
Naya [18.7K]

Answer: 54678 years

Step-by-step explanation:

This can be solved by the following equation:

N_{t}=N_{o}e^{-\lambda t} (1)

Where:

N_{t}=54\%=0.54 is the quantity of atoms of carbon-14 left after time t

N_{o}=1 is the initial quantity of atoms of C-14 in the mammal hide

\lambda is the rate constant for carbon-14 radioactive decay

t is the time elapsed

On the other hand, \lambda has a relation with the half life h of the C-14, which is 5730 years:

\lambda=\frac{ln(2)}{h}=\frac{ln(2)}{5730 years}=1.21(10)^{-4} years^{-1}=0.000121 years^{-1} (2)

Substituting (2) in (1):

0.54=1e^{-(0.000121 years^{-1}) t} (3)

Applying natural logarithm on both sides of the equation:

ln(0.54)=ln(1e^{-(0.000121 years^{-1}) t}) (4)

-0.616=-(0.000121 years^{-1}) t (5)

Isolating t:

t=\frac{-0.616}{-0.000121 years^{-1}} (6)

t=54677.68 years \approx 54678 years (7)  This is the age of the mammal hide

8 0
3 years ago
What method did you use to get the answer that I submitted.
raketka [301]

Answer:

y

Step-by-step explanation:

y

8 0
3 years ago
The length of a rectangle is twice its width. If the width is 10, what is the area?
Montano1993 [528]
10*2=20
20*10=200
i think the answer is E
7 0
3 years ago
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