Answer:
Yes,there is a significant association shell weight and the widths of the opercula
Step-by-step explanation:
Using a correlation Coefficient calculator :
Given the data above :
The Coefficient of correlation(r) obtained is :
0.7632
Obtaining the test statistic :
T = r² / √(1 - r²) / (n - 2)
T = 0.7632² / √(1 - 0.7632²) / (10 - 2)
T = 0.58247424 / 0.2284528
Test statistic = 2.550
The Pvalue from r score , N = 10
Pvalue(0.7632, 10) = 0.01022
α = 0.05
If Pvalue < α ; reject H0
Pvalue < α ; We conclude that there is a significant association shell weights and the widths of the opercula
He will spend $5.45 if he is driving 85 miles.
How can we figure this out mathematically?
4.36/68=0.064
That means every mile he drives he spends on average 6 cents.
Now 0.064 * 85 equals $5.45.
Please vote my answer brainliest! Thanks.
The answer to the question is -343i
<h3>
Answer: Choice A. 13 & 5/8 inches</h3>
Ideally you should always post the diagram to help us see the entire problem; however, the diagram is not needed in this case because we are told the figure is regular decagon. So there are 10 sides and each side is the same length. If each side is x inches long, then the perimeter is 10x inches.
10x = 136 & 1/4
10x = 136 + 1/4
10x = 136 + 0.25
10x = 136.25
x = 136.25/10
x = 13.625
x = 13 + 0.625
x = 13 + 625/1000
x = 13 + 5/8
x = 13 & 5/8
