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3 years ago

A computer rounded the number 129.257 to the nearest hundredth. What is this number rounded to the nearest hundredth

Mathematics

2 answers:

erma4kov [3.2K]3 years ago

6 0

Answer:

129.26

Step-by-step explanation:

i think it's this i dont know i honestly forgot decimals

Luda [366]3 years ago

6 0

Answer: 129.26

Step-by-step explanation: .2 would be the tenths place, .05 is the hundredths place, and .007 is the thousandths place. With that being known, we know that we need to go two places past the decimal to get the answer to the nearest hundredth. When we round if the next number (our case 7) is a five or larger we round the number up. This means that we round the 5 to a 6 to get and answer of 129.26

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sertanlavr [38]

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2 years ago

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3 years ago

Sqrtx^2+6x+9 if x≥3<br><br><br><br> please help quick idk how to do this at all

katrin [286]

Answer:

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Step-by-step explanation:

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3 years ago

Radioactive Decay

SpyIntel [72]

Answer:

Percentage of (226Ra) after 900 years is 68%

Step-by-step explanation:

Let P(t) be the amount of (226Ra) present at any time t

Half life of (226 Ra) = 1599 years

If P₀ is initial amount of (226 Ra) then after 1599 years

P(1599)=P₀/2

Decay i amount of radioactive substance is related to time t as

$\frac{dP}{dt}=kP(t)\\\\\frac{1}{P}\,dP=kdt\\\\Integrating\,\, both\,\,sides\\\\ln|P|=kt+c\\\\P(t)=Ce^{kt}\\\\at \,\, t=0\,\, P(0)=P_{o}\\\\P(0)=Ce^{k0}\\\\P_{o}=C\\\\then\\\\P(t)=P_{o}e^{kt}$

To find value of k

$at\,\, t=1599\,years\\\\P(1599)=\frac{P_{o}}{2}\\\\then\\\\\frac{P_{o}}{2} =P_{o}e^{k(1599)}\\\\\frac{1}{2} =e^{k(1599)}\\\\ln|\frac{1}{2}|=k(1599)\\\\k=\frac{ln|\frac{1}{2}|}{1599}=-4.3\times 10^{-3}\\\\\implies P(t)=P_{o}e^{-4.3\times 10^{-3}t}\\\\at\,\, t=900 \\\\P(900)=P_{o}e^{-4.3\times 10^{-3}(900)}\\\\P(900)=0.68P_{o}$

Percentage of radioactive element is:

Amount after 900 years $=\frac{P(900)}{P_{o}}\times 100\\\\=\frac{0.68P_{o}}{P_{o}}\times 100\%\\\\=68\%$

3 0

3 years ago

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Karolina [17]

Answer:158 centimeters

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7 0

3 years ago

Read 2 more answers