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Masja [62]
3 years ago
14

What is the equation, in slope-intercept form, of the line that is perpendicular to the line y – 4 = –2/3(x – 6) and passes thro

ugh the point (−2, −2)?
y = –2/3x –10/3
y = –2/3x +10/3
y = 3/2x – 1
y = 3/2x + 1
Mathematics
2 answers:
Kaylis [27]3 years ago
3 0
Lets write the given equation in the y = mx + c form 
y - 4 = -2/3(x-6)
y - 4 = -2/3x + 4
y = -2/3x + 8
therefore the slope is -2/3 and intercept is +8
the perpendicular line passes through x = -2 and y = -2
then if the given graph has a slope of -2/3 the line that is perpendicular to that should have the reciprocal of the gradient and should be in the opposite direction. So m = +3/2
lets substitute x,y and m values for the new perpendicular line
y =mx + c
-2 = 3/2 * -2 +c
-2 = -3 +c
c = -2 +3 
c = 1
Therefore the equation for the perpendicular line is 
y = 3/2x + 1

zepelin [54]3 years ago
3 0

Answer:

y = 3/2x + 1

Step-by-step explanation:

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Answer:

The answer to the given problem 3x-4+2(x-5)=9x+8-2x is x=-11

Step-by-step explanation:

Given problem is 3x-4+2(x-5)=9x+8-2x

To solve the equation:

3x-4+2(x-5)=9x+8-2x

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Now taking the terms to one side

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The answer to the given problem 3x-4+2(x-5)=9x+8-2x is x=-11

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