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Aliun [14]
3 years ago
15

Ratio and proportion question​

Mathematics
1 answer:
rosijanka [135]3 years ago
6 0

Answer:

<em>Hi there mate, sorry but we can't see the question.... Please try to resend...</em>

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F(x) -x^2 -2x+13 help
melamori03 [73]

Answer:

x =1 or -3

Step-by-step explanation:

10 = -x^2 - 2x + 13

when you solve that equation^ you get your answer to be either 1 or -3. Since -3 is a negative number, I would just type in x = 1

4 0
3 years ago
Read 2 more answers
or the past 50 days, daily sales of laundry detergent in a large grocery store have been recorded (to the nearest 10). Units Sol
bagirrra123 [75]

Answer, step-by-step explanation:

A. With the previous exercise we can deduce that there is the situation of a number of sales in a grocery store, the relative frequency for the number of units sold, is shown below:

units sold. relative frequency. Acumulative frequency. interval of random numbers

30. 0.16. 0.16. 0.00 <0.16

40. 0.24. 0.4. 0.16 <0.4

50. 0.3. 0.7. 0.4 <0.7

60. 0.2. 0.9. 0.7<09

70. 0.1. 1. 0.9<1

B. For the next point, they give us some random numbers and then it is compared with the simulation of 10 days in sales:

random Units

number. sold

0.12. 30

0.96. 70

0.53. 50

0.80. 60

0.95. 70

0.10. 30

0.40. 50

0.45. 50

0.77. 60

0.29. 40

the two lists are compared so that opposite each one is the result of the simulation

3 0
3 years ago
Fission tracks are trails found in uranium-bearing minerals, left by fragments released during fission events. An article report
Harlamova29_29 [7]

Answer:

Mean track length for this rock specimen is between 10.463 and 13.537

Step-by-step explanation:

99% confidence interval for the mean track length for rock specimen can be calculated using the formula:

M±\frac{t*s}{\sqrt{N}} where

  • M is the average track length (12 μm) in the report
  • t is the two tailed t-score in 99% confidence interval (2.977)
  • s is the standard deviation of track lengths in the report (2 μm)
  • N is the total number of tracks (15)

putting these numbers in the formula, we get confidence interval in 99% confidence as:

12±\frac{2.977*2}{\sqrt{15}} =12±1.537

Therefore, mean track length for this rock specimen is between 10.463 and 13.537

4 0
3 years ago
Find the mean of the following data set. 8, 5, 15, 12, 10 12.5 10 14 50
cluponka [151]

Answer:

10

Step-by-step explanation:

8+5+15+12+10= 50 / 5 = 10

7 0
3 years ago
Solve for x.<br> 2x2 + x = 10
Stells [14]

Answer:

x = 2, x = -5/2

Step-by-step explanation:

2x² + x - 10 = 0

(2x + 5)(x - 2) = 0

2x + 5 = 0

2x = -5

x = -5/2

x - 2 = 0

x = 2

8 0
3 years ago
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