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3 years ago

HELP ASAP IM IN TR$OUBLE NOWWWWWW

Mathematics

1 answer:

VMariaS [17]3 years ago

3 0

Answer:

1. true 2. false 3, false 4.true 5.false 6.true

Step-by-step

here's the link on brainly for that answer

brainly.com/question/10606041?utm_source=android&utm_medium=share&utm_campaign=question

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The ratio of dogs to cats at the animal shelter is 2:5. If there are 35 cats, how many dogs are there?

vekshin1

Answer:

Step-by-step explanation:

there are 18 dogs

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3 years ago

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Did I do this question right it’s slope I need help checking it

Tamiku [17]

Answer:

It should be "The unit rate is 2/3 every 1 hour" everything else is correct.

Step-by-step explanation:

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3 years ago

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Which values are in the solution set of the compound inequality? Check all that apply. 4(x + 3) ≤ 0 or x + 1 > 3 –6 –3 0 3 8

Colt1911 [192]

we have

$4(x + 3) \leq 0$ -------> inequality 1

$x + 1 > 3$ -------> inequality 2

we know that

In this system of inequalities, for a value to be the solution of the system, it is enough that it satisfies at least one of the two inequalities.

let's check each of the values

case 1) x=-6

Substitute the value of x=-6 in the inequality 1

$4(-6 + 3) \leq 0$

$4(-3) \leq 0$

$-12 \leq 0$ -------> is ok

The value of x=-6 is a solution of the compound inequality-----> It is not necessary to check the second inequality, because the first one satisfies

case 2) x=-3

Substitute the value of x=-3 in the inequality 1

$4(-3 + 3) \leq 0$

$4(0) \leq 0$

$0 \leq 0$ -------> is ok

The value of x=-3 is a solution of the compound inequality-----> It is not necessary to check the second inequality, because the first one satisfies

case 3) x=0

Substitute the value of x=0 in the inequality 1

$4(0 + 3) \leq 0$

$4(3) \leq 0$

$12 \leq 0$ -------> is not ok

Substitute the value of x=0 in the inequality 2

$0 + 1 > 3$

$1 > 3$ --------> is not ok

The value of x=0 is not a solution of the compound inequality

case 4) x=3

Substitute the value of x=3 in the inequality 1

$4(3 + 3) \leq 0$

$4(6) \leq 0$

$24 \leq 0$ -------> is not ok

Substitute the value of x=3 in the inequality 2

$3 + 1 > 3$

$4 > 3$ --------> is ok

The value of x=3 is a solution of the compound inequality

case 5) x=8

Substitute the value of x=8 in the inequality 1

$4(8 + 3) \leq 0$

$4(11) \leq 0$

$44 \leq 0$ -------> is not ok

Substitute the value of x=8 in the inequality 2

$8 + 1 > 3$

$9 > 3$ --------> is ok

The value of x=8 is a solution of the compound inequality

case 6) x=10

Substitute the value of x=10 in the inequality 1

$4(10 + 3) \leq 0$

$4(13) \leq 0$

$52 \leq 0$ -------> is not ok

Substitute the value of x=10 in the inequality 2

$10+ 1 > 3$

$11 > 3$ --------> is ok

The value of x=10 is a solution of the compound inequality

therefore

the answer is

[-6,-3,3,8,10]

7 0

3 years ago

ILL GIVE POINTS HELP ME PLEASE PLEASEEE HELP ME

hjlf

Answer:

it think it is d bd10

Step-by-step explanation:

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If a researcher wishes to determine whether there is evidence that the mean family income in the U.S. is greater than $30,000, t

Doss [256]

Answer:

B) a one-tailed test should be utilized, in which the region of rejection is in the right (upper tail)

Step-by-step explanation:

Explanation:-

one tailed test:-

A test of any statistical hypothesis where the alternative hypothesis is one tailed test(right tailed or left tailed) is called a one tailed test.

For example, In a test for testing the mean of a population in a single tailed test.

we assume that the null hypothesis H0:μ = μ0 against the alternative hypothesis.

H1:μ > μ0 (right tailed)

H1:μ < μ0 (left tailed) is called one tailed test.

Two tailed test:-

In a test of statistical hypothesis where the alternative hypothesis is two tailed test.

we assume that the null hypothesis H0:μ = μ0

Alternative hypothesis H1 :μ ≠ μ0 is called two tailed test.

Given data

There is evidence that the mean family income in the U.S. is greater than $30,000

we will use right tailed test.

Null hypothesis :- H0:μ = μ0

Alternative hypothesis:-H1 : μ> 30,000 (right tailed test)

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3 years ago