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dlinn [17]
3 years ago
12

What is the remainder when (3x3-2x+4x-3)is divided by (x2+3x+3)

Mathematics
1 answer:
sergeinik [125]3 years ago
4 0
If you do long division youll get the remainder which is: 28x + 30
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PLEASE HELP ME I AM ON A TEST . WILL MARK BRAINLIEST
tekilochka [14]

Answer:

A. -2

B. -10

Step-by-step explanation:

Given the equation of the line

y=\dfrac{1}{2}x-1

Its slope is \frac{1}{2}.

A. Perpendicular line has the slope m, for which

\dfrac{1}{2}\cdot m=-1\Rightarrow m=-2

B. The equation of the perpendicular line will be in the form

y=-2x+b

This line passes through the point (-6,2), substitute its coordinates into the equation:

2=-2\cdot (-6)+b\\ \\2=12+b\\ \\b=2-12\\ \\b=-10

So, y-intecept is -10.

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4 years ago
Find the median, first quartile, third quartile, interquartile range, and any outliers for each set of data.
nadezda [96]

Here is what i figured out.

3 0
3 years ago
Read 2 more answers
Hello can anyone help me
Scilla [17]

Answer:

Its a

Step-by-step explanation:

since its moving 2 units to the right its only moving in the x direction so you just add 2 to each value of x  

5 0
3 years ago
Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2 h, and Car B traveled the dista
lidiya [134]
Recall your d = rt,  distance = rate * time.

notice, the distance are the same, say it was "d" miles.

and if car A is travelling at a speed of say "r" mph, then B is going at "r+15" mph.

\bf \begin{array}{lccclll}
&\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\
&------&------&------\\
\textit{Car A}&d&r&2\\
\textit{Car B}&d&r+15&1.5
\end{array}
\\\\\\
\begin{cases}
\boxed{d}=2r\\
d=1.5(r+15)\\
----------\\
\boxed{2r}=1.5(r+15)
\end{cases}
\\\\\\
2r=1.5r+22.5\implies 0.5r=22.5\implies r=\cfrac{22.5}{0.5}\implies \boxed{r=\stackrel{mph}{45}}

how far is B going?  well, r + 15.
5 0
4 years ago
Read 2 more answers
Please help!!!
AlladinOne [14]

it would be 13

Step-by-step explanation:

6 0
3 years ago
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