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3 years ago

The difference of two numbers is 596. The smaller of the numbers is 716. What is the other number?

Mathematics

1 answer:

harkovskaia [24]3 years ago

6 0

Answer:

1312

Step-by-step explanation:

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LenKa [72]

Answer:

234

Step-by-step explanation:

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3 years ago

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Damian is working two summer jobs, making $9 per hour babysitting and making $14 per hour clearing tables. In a given week, he c

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3 years ago

Lee and Lyn both invested their birthday money. Lee put his money in a savings account that earned 8% simple interest annually.

tatyana61 [14]

Lyn made a better investment.

Her money will grow quicker than Lee because the money grows by 8% annually, and then the next year 8% off of the new balance.

Lee's money will only grow by 8% from the original price.

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3 years ago

The variable Z varies jointly with X and Y Z equals 36 when x equals two and Y equals 3 write the equation that relates the vari

Veronika [31]

Answer:

Step-by-step explanation:

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3 years ago

A drawer contains 3 white shirts, 2 blue shirts, and 5 gray shirts. A shirt is randomly

shutvik [7]

Answer:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = $\frac{1}{4}$

Step-by-step explanation:

Given that

3 white, 2 blue and 5 gray shirts are there.

To find:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = ?

Solution:

Here, total number of shirts = 3+2+5 = 10

First of all, let us learn about the formula of an event E:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

$P(First\ White) = \dfrac{\text{Number of white shirts}}{\text {Total number of shirts left}}$

$P(First\ White) = \dfrac{3}{10}$

Now, this shirt is set aside.

So, total number of shirts left are 9 now.

$P(First\ White\ and\ second\ gray) = P(First White) \times P(Second\ Gray)\\\Rightarrow P(First\ White\ and\ second\ gray) = P(First White) \times \dfrac{\text{Number of gray shirts}}{\text{Total number of shirts left}}\\\\\Rightarrow P(First\ White\ and\ second\ gray) = \dfrac{3}{10} \times \dfrac{5}{9}\\\Rightarrow P(First\ White\ and\ second\ gray) = \dfrac{1}{2} \times \dfrac{1}{2}\\\Rightarrow P(First\ White\ and\ second\ gray) = \bold{\dfrac{1}{4} }$

So, the answer is:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = $\frac{1}{4}$

4 0

3 years ago