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4 years ago

Please help... i need it asap

Mathematics

1 answer:

pshichka [43]3 years ago

7 0

Can you compare the graphs?
let me know if you cant

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Stephanie is trying to hang holiday lights in her house. She places a 12-foot ladder against the house. The top of the ladder to

Softa [21]

Answer:3

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Write in vertex form (by completing the square)y=4x2+40x+96

Anestetic [448]

$y=4x^2+40x+96\\ \\ The \ vertex \ form \ of \ the \ function \ is: \\ \\y = a(x - h)^2 + k \\ \\vertex =(h, k) \ is \ given \ by: \\ \\h = \frac{-b}{2a} , \ \ \ k = c -\frac{b^2}{4a} \\ \\a=4 , \ \ b=40 , \ \ c=96$

$h = \frac{-40}{2 \cdot 4}=\frac{-40}{8}=-5 \\ \\ k = 96 -\frac{40^2}{4 \cdot 4} =96-\frac{1600}{16} =96-100=-4 \\ \\ y = 4(x - (-5) )^2 + (-5)=4(x +5 )^2 -5$

6 0

3 years ago

87/200,0.44,43.7%,21/50 least to greatest

LUCKY_DIMON [66]

21/50, 87/200, 43.7%, 0.44

hope this helps.

4 0

3 years ago

The sum of three consecutive even numbers is 48. what are the smallest of these numbers?

Mekhanik [1.2K]

14 + 16 + 18= 48 so the answer would be 14

7 0

3 years ago

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Suppose a certain capsule is manufactured so that the dosage of the active ingredient follows the distribution Y ~ N(μ = 10 mg,

lianna [129]

Answer:

(a) Probability that Y falls into the dangerous region is 0.0013.

(b) Probability that the mean Y-bar falls into the dangerous region is 0.00001.

Step-by-step explanation:

We are given that a certain capsule is manufactured so that the dosage of the active ingredient follows the distribution Y ~ N(μ = 10 mg, σ = 1 mg).

A dosage of 13 mg is considered dangerous.

Let Y = dosage of the active ingredient

The z-score probability distribution for normal distribution is given by;

Z = $\frac{ Y-\mu}{\sigma} } }$ ~ N(0,1)

where, $\mu$ = population mean = 10 mg

$\sigma$ = standard deviation = 1 mg

(a) Probability that Y falls into the dangerous region is given by = P(Y $\geq$ 13 mg)

P(Y $\geq$ 13 mg) = P( $\frac{ Y-\mu}{\sigma} } }$ $\geq$ $\frac{ 13-10}{1} } }$ ) = P(Z $\geq$ 3) = 1 - P(Z < 3)

= 1 - 0.9987 = 0.0013

The above probability is calculated by looking at the value of x = 3 in the z table which has an area of 0.9987.

(b) We are given that a dosage of 13 mg is considered dangerous. And we sample 49 capsules at random.

Let $\bar Y$ = sample mean dosage

The z-score probability distribution for sample mean is given by;

Z = $\frac{\bar Y-\mu}{\frac{\sigma}{\sqrt{n} } } } }$ ~ N(0,1)

where, $\mu$ = population mean = 10 mg

$\sigma$ = standard deviation = 1 mg

n = sample of capsules = 49

So, Probability that the mean Y-bar falls into the dangerous region is given by = P( $\bar Y$ $\geq$ 13 mg)

P(Y $\geq$ 13 mg) = P( $\frac{\bar Y-\mu}{\frac{\sigma}{\sqrt{n} } } } }$ $\geq$ $\frac{13-10}{\frac{1}{\sqrt{49} } } } }$ ) = P(Z $\geq$ 21) = 1 - P(Z < 21)

= 0.00001

6 0

3 years ago