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defon
3 years ago
15

Wayne has a recipe that says to heat the oven to 160°C. Wayne evaluates the expression 1.8C + 32 when C= 160 to convert the temp

erature to degrees Fahrenheit To which temperature should Wayne heat the oven?​
Mathematics
1 answer:
tekilochka [14]3 years ago
5 0
1.8C+32. 1.8x25+32. 45+32
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Answer:

Domain: B but should be x > 0

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Step-by-step explanation:

The domain is the set of all x values. This is seen in the graph as all values on the x-axis which have a value for the function. Since this function begins at the y-axis (where x = 0) and continues right then the domain is x > 0.

The range is the set of all y values. This is seen in the graph as all values on the y-axis which have a value for the function. Since the function curves on the coordinate plane all along the y-axis, it has no restrictions. This means it has all y values as a part of the function. The range is all real numbers.

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What is the measurement of the third angle of a triangle if the first two angles measure 63 degrees and 87 degrees?
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Step-by-step explanation:

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liq [111]

For the given equation;

(3x-5)^2=-125

We shall begin by expanding the parenthesis on the left side, after which we would combine all terms on and move all of them to the left side, which shall yield a quadratic equation. Then we shall solve.

Let us begin by expanding the parenthesis;

\begin{gathered} (3x-5)^2\Rightarrow(3x-5)(3x-5) \\ (3x-5)(3x-5)=9x^2-15x-15x+25 \\ (3x-5)^2=9x^2-30x+25 \end{gathered}

Now that we have expanded the left side of the equation, we would have;

\begin{gathered} 9x^2-30x+25=-125 \\ \text{Add 125 to both sides and we'll have;} \\ 9x^2-30x+25+125=-125+125 \\ 9x^2-30x+150=0 \end{gathered}

We shall now solve the resulting quadratic equation using the quadratic formula as follows;

\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \text{Where;} \\ a=9,b=-30,c=150 \\ x=\frac{-(-30)\pm\sqrt[]{(-30)^2-4(9)(150)}}{2(9)} \\ x=\frac{30\pm\sqrt[]{900-5400}}{18} \\ x=\frac{30\pm\sqrt[]{-4500}}{18} \\ x=\frac{30\pm\sqrt[]{-900\times5}}{18} \\ x=\frac{30\pm\sqrt[]{-900}\times\sqrt[]{5}}{18} \\ x=\frac{30\pm30i\sqrt[]{5}}{18} \\ \text{Therefore;} \\ x=\frac{30+30i\sqrt[]{5}}{18},x=\frac{30-30i\sqrt[]{5}}{18} \\ \text{Divide all through by 6, and we'll have;} \\ x=\frac{5+5i\sqrt[]{5}}{3},x=\frac{5-5i\sqrt[]{5}}{3} \end{gathered}

ANSWER:

x=\frac{5+5i\sqrt[]{5}}{3},x=\frac{5-5i\sqrt[]{5}}{3}

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1 year ago
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Answer:

-2 1/8

<h2><em><u>Could I please have BRAINLIEST?</u></em></h2>

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