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Natalka [10]
3 years ago
8

problem 5 answer based of the following distribution. what would be the appropriate measures of center of spread circle one answ

er

Mathematics
1 answer:
pentagon [3]3 years ago
8 0

Answer:

b

Step-by-step explanation:

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A circuit of voltage V volts and resistance R
enot [183]

Answer:a) 3 amp

b) 3 volts

Step-by-step explanation:

As the relationship is given by

V= I*R

a)

I=240/80=3amp

b)

V= 0.6*5 = 3 volts

8 0
3 years ago
-9 − f − 7 = -7f + 8
Alex73 [517]
Answer: 4

Step by step explanation

-9-f-7=-7f+8
7f-f=9+8+7
6f=24
f=24/6
f=4
3 0
4 years ago
e is a math tutor. She charges each student $210 for the first 7 hours of tutoring and $20 for each additional hour. When the nu
dmitriy555 [2]
Part 1 :
if the number of hours (h) is greater than 7.
Equation for the amount(A) in dollar is
Amount (A) = 210 + (h-7)x20

Part 2 :
if she earns 410,
with the same equation
410 = 210 + (h-7)x 20
200 =(h-7)x 20
10 = h-7
17 = h
therefore, number of hours tutored is 17.
7 0
3 years ago
Medical researchers have determined that for exercise to be beneficial, a person’s desirable heart rate, R, in beats per minute,
yan [13]

we are given with two equations: R=143-0.65a for women and R = 165-0.75a for men. In this prblem we are asked the age of a man when R is equal to 135. In this case, we use the second equation and substitute R with 135. In this case, 135 = 165 - 0.75 a; a is equal then to 40 yrs old. In 2, when x is equal to 4, then 0.5*4 + 3 is equal to 5. 
6 0
4 years ago
A 1400 kg car moving +13.7 m/s makes an elastic collision with a 3200 kg truck, initially at rest. What is the velocity of the c
Kamila [148]

Answer:

The velocity of the car after the collision is -5.36 m/s

Step-by-step explanation:

An elastic collision is an encounter between two bodies in which the total kinetic energy of the two bodies remains the same.

let the following:

m₁ = mass of the car = 1400 kg

m₂ = mass of the truck = 3200 kg

u₁ = velocity of the car before collision = 13.7 m/s

u₂ = velocity of the truck before collision = 0 m/s

v₁ = velocity of the car after collision

v₂ = velocity of the truck after collision

v₁ = [ u₁ * (m₁ - m₂) + u₂ * 2m₂ ]/ (m₁ + m₂)

   =  [ 13.7 * (1400 - 3200) + 0 * 2 * 3200 ]/ (1400 + 3200)

   = - 5.36 m/s

So, <u>the velocity of the car after the collision is -5.36 m/s</u>

7 0
3 years ago
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