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3 years ago

For a parking payment app, what option would MOST likely connect a user to a third party/external gateway?

Computers and Technology

1 answer:

Alik [6]3 years ago

3 0

Answer:

The answer to this question is given below in the explanation section.

Explanation:

Almost all app that is doing online business integrated third party payment gateway and login/services. But some apps, don't integrate the third party login/signin services such as go ogle or face book login/sign in services.

But in the context of this question, for a parking payment app, upon reservation of parking space, the pay option connects a user to a third party/external gateway. This gateway will accept payment from the user and upon confirmation of payment, the parking space will get reserved.

so the correct option to this question is:

Pay

While the other options are incorrect because:

The sign-in option does not connect the user to a third pay/gateway in case if the app has self-registration and sign-in functionality. Rate and Time remaining are features of the app that does not force the user to connect third-party gateway.

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which classification of money describes money that can be accessed quickly and easily, and includes coins and paper money as wel

zhenek [66]

Money that can be promptly and easily appraised falls under the M1 Money classification.

<h3>What are broad and narrow money, respectively?</h3>

Broad money typically refers to M2, M3, and/or M4. The most liquid kinds of money, such as currency (banknotes and coins), as well as bank account balances that may be instantly changed into currency or used for cashless transactions, are generally referred to as "narrow money" (overnight deposits, checking accounts).

<h3>Describe Narrow Money.</h3>

All of the actual money that the central bank has falls under the category of "narrow money," which is a subset of the money supply. Demand deposits, money, and other liquid assets are included. In the US, "narrow money" is referred to as M1 (M0 plus demand accounts).

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1 year ago

When parking ur vehicle facing downhill with a curb, you should point ur front wheels?

Genrish500 [490]

Wheels should be pointing towards the curb. this is in case your vehicle rolls, if it does, the wheel will hit the curb and stop the car, it will also prevent the car from going into the road and incoming traffic. vice versa when parking uphill, point wheels away from curb, that is also to prevent the car from rolling to incoming traffic.

6 0

3 years ago

Read 2 more answers

A large population of ALOHA users manages to generate 50 requests/sec, including both originals and retransmissions. Time is slo

krok68 [10]

Answer:

The answer is below

Explanation:

Given that:

Frame transmission time (X) = 40 ms

Requests = 50 requests/sec, Therefore the arrival rate for frame (G) = 50 request * 40 ms = 2 request

a) Probability that there is success on the first attempt = $e^{-G}G^k$ but k = 0, therefore Probability that there is success on the first attempt = $e^{-G}=e^{-2}=0.135$

b) probability of exactly k collisions and then a success = P(collisions in k attempts) × P(success in k+1 attempt)

P(collisions in k attempts) = [1-Probability that there is success on the first attempt]^k = $[1-e^{-G}]^k=[1-0.135]^k=0.865^k$

P(success in k+1 attempt) = $e^{-G}=e^{-2}=0.135$

Probability of exactly k collisions and then a success = $0.865^k0.135$

c) Expected number of transmission attempts needed = probability of success in k transmission = $e^{G}=e^{2}=7.389$

6 0

3 years ago

Write a function named enterNewPassword. This function takes no parameters. It prompts the user to enter a password until the en

zloy xaker [14]

Answer:

def enterNewPassword():

while True:

password = input("Enter password: ")

has_digit = False

for i in password:

if i.isdigit():

has_digit = True

break

if not has_digit or (len(password) < 8 or len(password) > 15):

if len(password) < 8 or len(password) > 15:

print("The password length must be between 8 and 15!")

if not has_digit:

print("The password must include at least one digit!")

else:

return password

print(enterNewPassword())

Explanation:

*The code is in Python.

Create a function named enterNewPassword that takes no parameter

Create an indefinite while loop. Inside the loop, ask the user to enter the password. Initialize the has_digit as False, this will be used to check if password contains a digit or not. Create a for loop, that that iterates through the password, if one character is digit, set the has_digit as True and stop the loop (Use isdigit() to check if the character is digit or not).

After the for loop, check if has_digit is false or the length of the password is not between 8 and 15. If the length of the password is not between 8 and 15, print the error. If has_digit is false, again print the error.

Otherwise, password met the requirements and return the password

Call the enterNewPassword() function and print the result

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3 years ago

Anyone knows the answer for 6.1.4 Happy Birthday! codehs

Neko [114]

cvm is good cvm is great

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2 years ago