Please help! NEED IT IMMEDIATELY

Free points !!!!! <img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B9%7D%20" id="TexFormula1" title=" \sqrt{9} " alt=" \

Liono4ka [1.6K]

The answer is 3 hahahahaha

8 0

3 years ago

Read 2 more answers

Suppose that the probability that any particle emitted by a radioactive material will penetrate a certain shield is 0.01. If 10

AnnyKZ [126]

Answer:

a)P=0.42

b) $n\geq 297$

Step-by-step explanation:

We have a binomial distribution, since the result of each experiment admits only two categories (success and failure) and the value of both possibilities is constant in all experiments. The probability of getting k successes in n trials is given by:

$P=\begin{pmatrix}n\\ k\end{pmatrix} p^k(1-p)^{n-k}=\frac{n!}{k!(n!-k!)}p^k(1-p)^{n-k}$

a) we have k=2, n=10 and p=0.01:

$P=\frac{10!}{2!(10!-2!)}0.01^2(1-0.01)^{10-2}\\P=\frac{10!}{2!*8!}0.01^2(0.99)^{8}\\P=45*0.01^2(0.99)^8=0.42$

b) We have, $1-(1-p)^n=P$ , Here P is the probability that at least one particle will penetrate the shield, this probabity has to be equal or greater than 0.95. Therefore, this will be equal to subtract from the total probability, the probability that the particles do not penetrate raised to the total number of particles.

$1-0.99^n\geq 0.95\\0.99^n\leq 1-0.95\\0.99^n\leq 0.05\\n\geq 297$

4 0

2 years ago

A researcher wants to determine whether the number of minutes adults spend online per day is related to gender. A random sample

suter [353]

Answer:

The expected frequency for the cell E2,2 is = 33

Step-by-step explanation:

The given data is

Gender | 0-30| 30-60| 60-90| 90+ Totals

Male | 23 | 35 | 76 | 46 180

Female | 31 | 42 | 46 | 16 135

Totals 54 77 122 62 315

The expected frequency for the cell E2,2 is :

Expected for the (30-60 box for females) = Total of (30-6)/ (total )* females

= ( 77/315)135= 33

Here p= 77/315 and n= 135

therefor X= pn = 33

χ²= (33-42)²/33= 2.455 ( for the single value of E2,2=33)

Expected for the (30-60 box for males) = Total of (30-6)/ (total )* males

= ( 77/315)180= 44

χ²= (44-42)²/44= 0.09

The critical region is χ² (0.05) 3 ≥ χ²= 11.34

Let the null and alternate hypothesis be

H0:the number of minutes spent online per day is not related to gender

against

Ha: the number of minutes spent online per day is related to gender

The single value of χ² for E2,2 = 2.45 is less than the critical value of 11.34.

6 0

2 years ago

The length of the base of an isosceles triangle is x. The length of a leg is 2x-6. The perimeter of the triangle is 38. Find X

Norma-Jean [14]

Answer:

x = 10

Step-by-step explanation:

Perimeter of a triangle = the sum of the three sides.

In an isosceles the legs are equal (2x - 6) and the base is x

Perimeter = (x) + (2x - 6) + (2x - 6)

38 = 5x - 12

38 + 12 = 5x

50 = 5x

$\frac{50}{5} = \frac{5x}{5}$

10 = x

8 0

3 years ago

The sum of fifteen and six times a number t is eighty one what is the number

yKpoI14uk [10]

Answer: t=11 :))

Step-by-step explanation:

15+6t=81

6t=81-15

6t=66

6t/6=66/6

t=11

7 0

3 years ago