Question

BRAINLIEST! 1. Estimate the sum or difference. Use the benchmarks 0, 1/2 and 1

Answer 1

Answer:

A) The sum or difference of the numbers is $\frac{1}{2}$ , option B

B)  The total distance cover by Tom is 1 $\frac{2}{35}$ miles

C)  The longer duration of Tom on Monday than Tuesday is $\frac{5}{8}$ hours , option B              

Step-by-step explanation:

Given as :

A) The given benchmarks as 0 , $\frac{1}{2}$ , 1

From the given number , the mid number is  $\frac{1}{2}$

So, The sum of the number = 0 +  $\frac{1}{2}$

I,e The sum of the number =   $\frac{1}{2}$

And The difference of number = 1 -  $\frac{1}{2}$

Or, The difference of number =   $\frac{2 - 1}{2}$

Or, The difference of number = $\frac{1}{2}$

Hence The sum or difference of the numbers is $\frac{1}{2}$  Answer

B) The distance cover by Tom on Monday = $\frac{1}{5}$ miles

The distance cover by Tom on Tuesday = $\frac{6}{7}$ miles

So, The total distance cover = The distance cover on Monday + The distance cover on Tuesday

I.e  The total distance cover =  $\frac{1}{5}$ miles +  $\frac{6}{7}$ miles

Now, taking LCM

Or, The total distance cover =  $\frac{7 + 30}{35}$ miles

Or, The total distance cover =  $\frac{37}{35}$ miles

I.e The total distance cover =  1 $\frac{2}{35}$ miles

Hence The total distance cover by Tom is 1 $\frac{2}{35}$ miles Answer

C) The time period of Tom reading on Monday = $\frac{7}{8}$ hours

The time period of Tom reading on Tuesday = $\frac{2}{8}$ hours

The longer duration of Tom on Monday than Tuesday = x hours

So, x =   The time period of Tom reading on Monday -  The time period of Tom reading on Tuesday

I.e x = $\frac{7}{8}$ hours - $\frac{2}{8}$ hours

∴ x = $\frac{7 - 2}{8}$ hours

I,e x = $\frac{5}{8}$ hours

So, The longer duration of Tom on Monday than Tuesday = x =  $\frac{5}{8}$ hours

Hence  The longer duration of Tom on Monday than Tuesday is $\frac{5}{8}$ hours   . option B  Answer