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2 years ago

Tan22° + tan23° tan22°. tan23° = 1 prove that

Mathematics

1 answer:

inysia [295]2 years ago

5 0

Answer:

Formula:(from trigonometry)

Tan(A+B)=(tanA+tanB)/(1-tanA*tanB)

Let A=22 degrees,B=23 degrees

Tan(22+23)=(tan22+tan23)/(1-tan22*tan23)

From trigonometry we know tan45=1

Therefore tan(45)=1=(tan22+tan23)/(1-tan22tan23)

=> 1-tan22tan23=tan22+tan23

=> tan22+tan23+tan23tan22 =1

Hence proved

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Explanation:

From the question, we're told that triangles AMY and MEG are similar. If triangle AMY has sides AM = 5, MY = 7, and AY = 3 then we can find the side lengths of triangle MEG since we're told from the question that it is a dilation of AMY by a scale factor of 1/3.

So all we need to is multiply the corresponding sides of AMY by 1/3, so we'll have;

$\begin{gathered} ME=5\ast\frac{1}{3}=\frac{5}{3} \\ EG=7\ast\frac{1}{3}=\frac{7}{3} \\ MG=3\ast\frac{1}{3}=3 \end{gathered}$

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$\begin{gathered} \text{Perimeter of MEG}=\frac{5}{3}+\frac{7}{3}+3 \\ =\frac{5+7+9}{3} \\ =\frac{21}{3} \\ =7 \end{gathered}$

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1 year ago

Tan22° + tan23° tan22°. tan23° = 1 prove that ​

Tan22° + tan23° tan22°. tan23° = 1 prove that