Question

I’ve gotten this answer wrong twice already

Answer 1

Answer:

Step-by-step explanation:

The standard vertex form of a quadratic (which is what your graphs are) is

$y=(x-h)^2+k$ where h and  are the coordinates of the vertex. The vertex is really all we need to fill in this equation. Looking at the blue graph, the vertex is located at (-4, 1), so h = -4 and k = 1. Filling in the equation:

$y=(x-(-4))^2+1$ which simplifies down to

$y=(x+4)^2+1$. It's that simple.I think that's choice C (I'm not sure; it's very tiny!)