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2 years ago

What is the constant of proportionality?

Mathematics

2 answers:

Korolek [52]2 years ago

8 0

Answer:

0.4

1*3 = 3

7*? = 7n (7 of a variable)

3 = 7n (divide by 7)

3/7 = 0.4285

0.4285 rounded to the nearest tenth = 0.4

MrRa [10]2 years ago

6 0

0 or 2.33333333

2.33333333 rounded to ten is 0

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at a local fitness center, members pay a $12 membership fee and $5 for each aerobic class. Nonmembers pay $6 for each aerobic cl

Len [333]

Make an equation:

5x+12=6x

Use the subtraction property:

x=12

The final answer is that the cost for members and nonmembers will be the same when there have been 12 classes.

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3 years ago

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When *Attached image* is solved for w, one equation is ______. Which of the following is an equivalent equation to find w?

m_a_m_a [10]

It is the second answer:

8x²/y -2 is a solution which is equivalent to (8x²-2y)/2. Proof:

Reduce 8x²/y -2 to the same denominator:

8x²/y - 2y/y = (8x² - 2y)/y

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3 years ago

An instructor gives her class the choice to do 7 questions out of the 10 on an exam.

Maksim231197 [3]

Answer:

(a) 120 choices

(b) 110 choices

Step-by-step explanation:

The number of ways in which we can select k element from a group n elements is given by:

$nCk=\frac{n!}{k!(n-k)!}$

So, the number of ways in which a student can select the 7 questions from the 10 questions is calculated as:

$10C7=\frac{10!}{7!(10-7)!}=120$

Then each student have 120 possible choices.

On the other hand, if a student must answer at least 3 of the first 5 questions, we have the following cases:

1. A student select 3 questions from the first 5 questions and 4 questions from the last 5 questions. It means that the number of choices is given by:

$(5C3)(5C4)=\frac{5!}{3!(5-3)!}*\frac{5!}{4!(5-4)!}=50$

2. A student select 4 questions from the first 5 questions and 3 questions from the last 5 questions. It means that the number of choices is given by:

$(5C4)(5C3)=\frac{5!}{4!(5-4)!}*\frac{5!}{3!(5-3)!}=50$

3. A student select 5 questions from the first 5 questions and 2 questions from the last 5 questions. It means that the number of choices is given by:

$(5C5)(5C2)=\frac{5!}{5!(5-5)!}*\frac{5!}{2!(5-2)!}=10$