The account balance after 3 years if the interest is compounded continuously is $5,142.62
<h3>How to find compound interest?</h3>
- Principal, P = $4,700
- Time,t = 3 years
- Interest rate, r = 3%
r = 3/100
r = 0.03 rate per year,
A = Pe^rt
A = 4,700.00(2.71828)^(0.03)(3)
= 12,775.916^0.09
A = $5,142.62
Therefore, the account balance after 3 years if the interest is compounded continuously is $5,142.62
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Answer:
23.7 -2.5 X 8 = 23.7 - 20
= 3.7
Answer:
9r
Step-by-step explanation:
4r+9r-11r+7r
Combine like terms
13r -11r+7r
2r+7r
9r
Answer:
Step-by-step explanation:
Area of sector = angle/360 * pi * r^2
7.1 = 40/360 * 22/7 * r^2
7.1 = 1/9 * 22/7 * r^2
63.9 = 22r^2/7
r^2 = (7 * 63.9)/22
r^2 = 20.331818181818
r = square root of 20.331818181818
r = 4.51
d = r * 2 = 4.51 * 2 = 9.02
