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makvit [3.9K]
3 years ago
14

A circle's circumference is approximately 88 cm. Estimate the diameter, rounding to the nearest WHOLE number. (don't forget your

units and use 3.14 if you need to use )
Mathematics
2 answers:
brilliants [131]3 years ago
8 0

Answer:

  • 28 cm

Step-by-step explanation:

<u>Circumference formula:</u>

  • C = πd

<u>Substitute values of circumference and the π to find the diameter:</u>

  • d = C/π
  • d = 88/3.14 = 28 cm (rounded)
Snezhnost [94]3 years ago
3 0

Answer:

diameter = 28 cm

Step-by-step explanation:

circumference = 2πr

88 cm = 2 * 3.14.*r. ( π = 3.14 )

r = ( 88)/(3.14*2)

r = 14 cm

diameter = 2 * radius

diameter = 2 * 14 cm

diameter = 28 cm

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sergiy2304 [10]

Answer:

See explanation

Step-by-step explanation:

a) To prove that DEFG is a rhombus, it is sufficient to prove that:

  1. All the sides of the rhombus are congruent:  |DG|\cong |GF| \cong |EF| \cong |DE|
  2. The diagonals are perpendicular

Using the distance formula; d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

|DG|=\sqrt{(0-(-a-b))^2+(0-c)^2}

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|GF|=\sqrt{((a+b)-0)^2+(c-0)^2}

\implies |GF|=\sqrt{a^2+b^2+c^2+2ab}

|EF|=\sqrt{((a+b)-0)^2+(c-2c)^2}

\implies |EF|=\sqrt{a^2+b^2+c^2+2ab}

|DE|=\sqrt{(0-(-a-b))^2+(2c-c)^2}

\implies |DE|=\sqrt{a^2+b^2+c^2+2ab}

Using the slope formula; m=\frac{y_2-y_1}{x_2-x_1}

The slope of EG is m_{EG}=\frac{2c-0}{0-0}

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The slope of EG is undefined hence it is a vertical line.

The slope of  DF is m_{DF}=\frac{c-c}{a+b-(-a-b)}

\implies m_{DF}=\frac{0}{2a+2b)}=0

The slope of DF is zero, hence it is a horizontal line.

A horizontal line meets a vertical line at 90 degrees.

Conclusion:

Since |DG|\cong |GF| \cong |EF| \cong |DE| and DF \perp FG , DEFG is a rhombus

b) Using the slope formula:

The slope of DE is m_{DE}=\frac{2c-c}{0-(-a-b)}

m_{DE}=\frac{c}{a+b)}

The slope of FG is m_{FG}=\frac{c-0}{a+b-0}

\implies m_{FG}=\frac{c}{a+b}

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75/100×300=225

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