About 127.3(square root of 16,200, or 90√2) Look at this problem like a right triangle. Each leg is 90 feet, so the hypotenuse is the square root of 90^2 + 90^2
About 52.3(square root of 2735.64) Another right triangle problem! Once again, with Pythagorean theorem (a^2 + b^2 = c^2) You can deduce that 60^2 = 29.4^2 + the width of the TV^2.
About 11.6(Square root of 134.75)Another right triangle problem, you can deduce that 9.5^2 + The pool length^2 = 15^2

Hope it helps <3

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7 0

3 years ago

Read 2 more answers

How many solutions does the following equation have? 5 x + 8 − 7 x = − 4 x + 1 5x+8−7x=−4x+15, x, plus, 8, minus, 7, x, equals,

UNO [17]

Answer: There is one valid solution to the equation 5x + 8 - 7x = -4x + 1, x = -3.5.

Step-by-step explanation:

8 0

1 year ago

Which function grows

mojhsa [17]

Y = 8x + 29 is the answer for your question

4 0

2 years ago

An English professor assigns letter grades on a test according to the following scheme. A: Top 15% of scores B: Scores below the

lisabon 2012 [21]

Answer:

59 to 66

Step-by-step explanation:

Mean test scores = u = 74.2

Standard Deviation = $\sigma$ = 9.6

According to the given data, following is the range of grades:

Grade A: 85% to 100%

Grade B: 55% to 85%

Grade C: 19% to 55%

Grade D: 6% to 19%

Grade F: 0% to 6%

So, the grade D will be given to the students from 6% to 19% scores. We can convert these percentages to numerical limits using the z scores. First we need to to identify the corresponding z scores of these limits.

6% to 19% in decimal form would be 0.06 to 0.19. Corresponding z score for 0.06 is -1.56 and that for 0.19 is -0.88 (From the z table)

The formula for z score is:

$z=\frac{x-u}{\sigma}$

For z = -1.56, we get:

$-1.56=\frac{x-74.2}{9.6}\\\\ x = 59$

For z = -0.88, we get:

$-0.88=\frac{x-74.2}{9.6}\\\\ x = 66$

Therefore, a numerical limits for a D grade would be from 59 to 66 (rounded to nearest whole numbers)

7 0

3 years ago