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trasher [3.6K]
3 years ago
14

The weight of an empty pickup truck is 2.1 times the weight of an empty car. If the empty car weighs 1.8 tons, how many tons doe

s the pickup weigh carrying a 0.5 ton load
Mathematics
2 answers:
Mandarinka [93]3 years ago
7 0

Answer:

4.28 tons

Step-by-step explanation:

We are given that

Weight of empty car=1.8 tons

Weight of empty truck =2.1\times 1.8=3.78 tons

We have to find weight  of pickup when it carrying 0.5 tons load.

Weight of pickup  when it carrying 0.5 tons load carrying

=Weight of empty pickup truck+ Weight of load

Weight of pickup when it carrying 0.5 tons load

=3.78+0.5=4.28 tons

Hence, the weight of pickup when it carrying 0.5 tons load=4.28 tons

Artemon [7]3 years ago
6 0
4.68 tons since you would multiply 2.1+0.5=2.6×1.8=4.68 tons
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2) Choice a.

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1) P(0) is the population initially.

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\frac{P(1)}{P(0)} represents the population increase factor.

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2) Let's figure out the population growth in terms of months instead of years.

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We want t to represent months.

A full year is 12 months, in a full year we have that P(1)=10000(0.2)^1=10000(0.2)=2000

So we want a new P such that P(12)=2000 since 12 months equals a year.

Let's look at the functions given to see which gives us this:

a) P(12)=10000(0.87449)^{12}=2000 \text{approximately}

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So a is the function we want.

Also another way to look at this:

P(t)=10000(.2)^t where t is in years.

P(t)=10000(.2^\frac{1}{12})^t where t is in months.

And .2^\frac{1}{12}=0.874485 \text{approximately}

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