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N76 [4]
3 years ago
8

22 percent of what number is 24.2

Mathematics
2 answers:
lawyer [7]3 years ago
6 0
110 is the correct answer.
anastassius [24]3 years ago
5 0
22% of what number is 24.2

0.22x = 24.2
x = 24.2 / 0.22
x = 110 <===
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Which expression is equivalent to -36 - 8?
Deffense [45]
-36-8 = -44

-36+(-8) = -44
third option
7 0
3 years ago
Which equation describes the circle having center point (3,7) and the radius r=4 in Standard form
Annette [7]

The equation of circle in standard form is (x - 3)^2 + (y - 7)^2 = 16

<h3><u>Solution:</u></h3>

Given that circle having center point (3,7) and the radius r = 4

To find: equation of circle in standard form

<em><u>The equation of circle is given as:</u></em>

(x - h)^2 + (y - k)^2 = r^2

Where center (h,k) and radius r units

Given that center point (h , k) = (3, 7) and radius r = 4 units

Substituting the values in above equation of circle,

(x - 3)^2 + (y - 7)^2 = 4^2\\\\(x - 3)^2 + (y - 7)^2 = 16

Thus the equation of circle in standard form is (x - 3)^2 + (y - 7)^2 = 16

6 0
3 years ago
2.654,2.564,2.056,2.465 from greatest to least
marusya05 [52]
2.654, 2.564,2.465, 2.065
8 0
3 years ago
Read 2 more answers
The answer choices are 11 1 2.48 6
Fudgin [204]

Answer:

The ball reached its maximum height of (11\ yards) in (1\ second).

Step-by-step explanation:

This question is essentially asking one to find the vertex of the parabola formed by the given equation. One could plot the equation, but it would be far more efficient to complete the square. Completing the square of an equation is a process by which a person converts the equation of a parabola from standard form to vertex form.

The first step in completing the square is to group the quadratic and linear term:

h(t)=-5t^2 + 10t + 6\\\\h(t) = (-5t^2 + 10t) + 6

Now factor out the coefficient of the quadratic term:

h(t)=-5(t^2 -2t) + 6

After doing so, add a constant such that the terms inside the parenthesis form a perfect square, don't forget to balance the equation by adding the inverse of the added constant term:

h(t) = -5(t^2 -2t) + 6\\\\h(t) = -5(t^2 -2t + 1 -1 ) + 6

Now take the balancing term out of the parenthesis:

\\\\h(t)=-5(t^2 -2t + 1) + 6 + ((-1)(-5))

Simplify:

h(t) = -5(t^2 -2t + 1) + 6 + 5\\\\h(t) = -5(t-1)^2 + 11

The x-coordinate of the vertex of the parabola is equal to the additive inverse of the numerical part of the quadratic term. The y-coordinate of the vertex is the constant term outside of the parenthesis. Thus, the vertex of the parabola is:

(1, 11)

8 0
3 years ago
Please help with 7-9 they are related to the same circle
Andrej [43]

40º

7) In this problem, we can see that both tangent lines to that circle come from the same point O.

So, we can write out the following considering that there is one secant line DO and one tangent line to the circle AO

\begin{gathered} m\angle1=\frac{1}{2}(160-80) \\ m\angle1=\frac{1}{2}(80) \\ m\angle1=40^{\circ} \end{gathered}

3 0
2 years ago
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