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2 years ago

Solve the system of equations by ELIMINATION.

Mathematics

1 answer:

Dafna1 [17]2 years ago

6 0

Step-by-step explanation:

4x + 2y = 10 --------(1)

2x + 3y = 33 -----------(2)

Multiply 2 with eq. (1) and 4 with eq. (2)

8x + 4y = 20 ____________(3)

8x + 12y = 132 ______(4)

Subtracting (3) from (4),

8x + 4y = 20

- 8x -12y = -132

----------------------

0 -8y = -112

y = 112/8

y = 4 is the answer.

Putting the vakue of y in eq. (2),

2x + 12 = 33

2x = 33-12

2x = 21

x = 21/2 is the answer.

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If f(x)=7-3x and g(x)=3x-7, what is the value of f(1)-g(1)?

postnew [5]

Substitute 1 for x in each of your equations.

f(x)=7-3x
which is
f(1)=7-3(1)
=3
Do the same for g(x)
g(x)=3x-7
which is
g(1)=3(1)-7
=-4

Then subtract g(x) from f(x):
3-(-4)
=7

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3 years ago

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ruslelena [56]

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3 years ago

Where v is the final velocity (in m/s), u is the initial velocity (in m/s), a is the acceleration (in m/s²) and s is the distanc

Anna11 [10]

Answer:

The final velocity v is 21.74 m/s.

Step-by-step explanation:

Given:

$\textrm{initial velocity} = u = 9\ m/s\\\textrm{acceleration} = a = 7\ m/s^{2}\\\textrm{distance} = s = 28\ m$

To find:

$\textrm{final velocity} = v = ?$

Solution:

As we know the third equation of motion is represented as

$v^{2} = u^{2} + 2\times a\times s\\$

Substituting the values u, a and s in the above equation we get

$v^{2} = 9^{2} + 2\times 7\times 28\\ =81 + 392\\=473\\$

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3 years ago

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hodyreva [135]

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3 years ago

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Alex_Xolod [135]

Answer: Below

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In mixed number form it's:

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2 years ago

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