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AVprozaik [17]
3 years ago
6

PLEASE HELP!!!!!! if you know how please write how you got

Mathematics
1 answer:
GarryVolchara [31]3 years ago
5 0

9514 1404 393

Answer:

  D.  John's boat was farther and faster

Step-by-step explanation:

The equation tells you that at x = 0, Roberta's boat was 10 miles from the dock. The words tell you John's boat started 20 miles from the dock, so his boat started farther away.

John's boat traveled a distance of (55 -20) = 35 miles in 5 hours, so the speed was (35 mi)/(5 h) = 7 mi/h. The equation tells you Roberta's boat traveled 6 miles for each hour, so John's boat was faster.

  John's boat was farther and traveled more quickly

__

<em>Additional comment</em>

The variables in Roberta's equation are not defined. In order for the problem to make sense, we must assume that x represents time in hours, and y represents distance in miles.

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2 years ago
Two trains leave a town at the same time heading in opposite directions. One train is traveling 12 mph faster than the
klemol [59]

Answer:

I'm going to paint you a picture in words of what this looks like on paper.  We have a train leaving from a point on your paper heading straight west.  We have another train leaving from the same point on your paper heading straight east.  This is the "opposite directions" that your problem gives you.  

Now let's make a table:

                distance       =        rate      *       time

Train 1

Train 2

We will fill in this table from the info in the problem then refer back to our drawing.  It says that one train is traveling 12 mph faster than the other train.  We don't know how fast "the other train" is going, so let's call that rate r.  If the first train is travelin 12 mph faster, that rate is r + 12.  Let's put that into the table

              distance        =        rate        *        time

Train 1                                        r

Train 2                                    (r + 12)

Then it says "after 2 hours", so the time for both trains is 2 hours:

         

              distance        =        rate        *        time

Train 1                                        r           *          2

Train 2                                  (r + 12)       *          2

Since distance = rate * time, the distance (or length of the arrow pointing straight west) for Train 1 is 2r.  The distance (or length of the arrow pointing straight east) for Train 2 is 2(r + 12) which is 2r + 24.  The distance between them (which is also the length of the whole entire arrow) is 232.  Thus:

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This means that Train 1 is traveling 52 mph and Train 2 is traveling 12 miles per hour faster than that at 64 mph

Step-by-step explanation:

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