Answer:
3960.4 bacteria
Step-by-step explanation:
The formula to solve the above question is given as:
P(t) = Po (2) ^t/k
P(t) = Population after time t = ?
Po = Initial population = 650 bacteria
t = Time in days = 7.3 days
k = doubling time = 2.8 days
P(t) = 650 × (2)^7.3/2.8
P(t) = 650 × 2^2.6071428571
P(t) = 650 × 6.0929582599
P(t) = 3960.4228689 bacteria.
Approximately = 3960.4 bacteria
Therefore, the number of bacteria the researcher will have after 7.3 days if they started with 650 bacteria is 3960.4 bacteria.
4 Dollars - 100%
3.60 Dollars - ?
Just Cross Multiply
4X = 360
X = 360/4
X = 90%
100%-90% = 10℅
The percent change is 10 percent
Answer: 0.25 or 1/4
Step-by-step explanation:
1/2*2 = 1/2^2 = 1/4
Answer:
x ≤ 75
Step-by-step explanation:
The computation of the inequality function is as follows:
Let us assume the remaining time left for other drills be x
Given that the team spends 20 minutes for running laps
And minimum of 15 minutes for discussing plays
Also practicing for last one hour and 45 minutes
Now as we know that
1 hour = 60 minutes
So total minutes would be
= 60 + 45
= 105 minutes
Total minutes spend by the team is
= 20 + 15
= 35 minutes
So now the remaining time left is
x ≤ 105 - 35
x ≤ 75
5y - 5= 22
or
5(y)-5=22
Hope that helps!
